What is 2/5 divided by 3/4

This figure represents a planter that is to be filled with soil. How much soil will it take to fill the planter? Enter your answ

jonny [76]

Answer:

1134 cubic inches of soil

Step-by-step explanation:

You can split the shape apart and then add the volumes together at the end.

The bottom shape is 21x7x2

=294

The top shape is 12x10, and the last side can be foundfrom the other shape’s depth, 7.

12x10x7

=840

294+840=1134

3 0

2 years ago

BOTH PLEASE 20 POINTS,TYSM

makkiz [27]

Answer:

5.) 13,841,287,201 x 2,401. 6.) 64⁴.

Step-by-step explanation:

PEMDAS requires parenthesis first, then exponents, then multiplication/division, and then addition/subtraction. For 5, lets find 7¹². According to my calculations, that is 13,841,287,201. Now for 7⁴. According to my calculations, that is 2,401. Now, we have 13,841,287,201 x 2,401. In math, an expression is a problem. If I solve it, it wouldn't be an expression, so I'll just leave it at that. For 6, we do the parenthesis first. 8² is 64. 64 to the fourth power is 16,777,216. If I solved it, it wouldn't be an expression, so we have to leave it at 64⁴. If you are wondering, 64⁴ is equal to 16,777,216. I hope this helps!

8 0

3 years ago

Rothamsted Experimental Station (England) has studied wheat production since 1852. Each year many small plots of equal size but

podryga [215]

Answer:

(a) 0.653

(b) 0.0198

(c) Yes, after testing we conclude that the population variance of annual wheat production for the first plot is larger than that for the second plot.

Step-by-step explanation:

(a) We are give the sample of one year annual production of wheat (in pounds) ;

4.46, 4.21, 4.40, 4.81, 2.81, 2.90, 4.93, 3.54, 4.16, 4.48, 3.26, 4.74, 4.97, 4.02, 4.91, 2.59

For calculating sample variance, firstly we will calculate mean of the above data;

Mean of above data, $X_1bar$ = Sum of all values ÷ n (no. of values)

= $\frac{4.46 + 4.21+4.40+.......+4.91+2.59}{16}$ = 4.074

Sample Variance, $s_1^{2}$ = $\frac{\sum (X-X_1bar)^{2} }{n-1}$ = $\frac{(4.46-4.074)^{2}+(4.21-4.074)^{2}+.........+(4.91-4.074)^{2}+(2.59-4.074)^{2} }{16-1}$ = 0.653

(b) Another sample for annual wheat production (in pounds);

3.89, 3.81, 3.95, 4.07, 4.01, 3.73, 4.02, 3.78, 3.72, 3.96, 3.62, 3.76, 4.02, 3.73, 3.94, 4.03

Mean of above data, $X_2bar$ = Sum of all values ÷ n (no. of values)

= $\frac{3.89+3.81+3.95.......+3.94+4.03}{16}$ = 3.88

Sample Variance, $s_2^{2}$ = $\frac{\sum (X-X_2bar)^{2} }{n-1}$ = $\frac{(3.89-3.88)^{2}+(3.81-3.88)^{2}+.........+(3.94-3.88)^{2}+(4.03-3.88)^{2} }{16-1}$ = 0.0198

(c) Now, we have to test the claim that population variance of annual wheat production for the first plot is larger than that for the second plot i.e.;

Null Hypothesis, $H_0$ : $\sigma_1^{2} = \sigma_2^{2}$ or $H_0$ : $\frac{\sigma_1^{2} }{\sigma_2^{2} } = 1$

Alternate Hypothesis, $H_0$ : $\sigma_1^{2} > \sigma_2^{2}$ or $H_0$ : $\frac{\sigma_1^{2} }{\sigma_2^{2} } > 1$

The test statistics used here is;

$\frac{s_1^{2} }{s_2^{2} }* \frac{\sigma_1^{2} }{\sigma_2^{2}}$ ~ $F_n__1-1_,n_2-1$ where, $n_1 = 16$ and $n_2 =16$

Test Statistics = $\frac{0.653 }{ 0.0198}* 1$ ~ $F_1_5_,_1_5$

= 32.98

Since, we are not provided with any significance level so we assume it to be 5% and at this level, the F table gives critical value of 2.4282.

<em>Since our test statistics is higher than the critical value and it falls in the rejection region so we have sufficient evidence to reject null hypothesis and conclude that the population variance of annual wheat production for the first plot is larger than that for the second plot.</em>

8 0

3 years ago

The cost of 4 math books plus 1 science book is 4 more than the cost of 2 math books plus 3 science books, if a science book is

cricket20 [7]

Answer:

Let M represents the cost of 1 Math book and S represents the cost of 1 science book.

As per the statement:

The cost of 4 math books plus 1 science book is 4 more than the cost of 2 math books plus 3 science books.

"Cost of 4 Math books plus 1 science book" translated to 4M+S

"4 more than the cost of 2 math plus 3 science books " translated to 2M+3S+4

then;

4M+S = 2M+3S+4

Subtract 2M from both sides we get;

2M + S = 3S+4

Subtract S from both sides we get;

2M = 2S + 4

It is also given the cost of science book is $22.95

⇒ $2M = 2(22.95)+4 = 45.9+4=49.9$

⇒2M = 49.9

Divide both sides by 2 we get;

$M = \$ 24.95$

therefore, the cost of the math book is $24.95

6 0

3 years ago

3(n+1)=15-n solve for n

nirvana33 [79]

Answer:

n = 3

Step-by-step explanation:

3(n+1) = 15 - n

3n + 3 = 15 - n

3n +n = 15 - 3

4n = 12

n = 3

5 0

3 years ago