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o-na [289]
3 years ago
5

The ladybugs are planting a garden. They have 25-cm-by-10 cm rectangle for flowers. Each flower needs exactly 1 square centimete

r for space. How many flowers can they plant?

Mathematics
2 answers:
astra-53 [7]3 years ago
8 0
Sent a picture of the solution to the problem (s).

jekas [21]3 years ago
6 0

Answer: They can plant 250 flowers.

Step-by-step explanation:

Given : The dimension of the rectangular garden = 25-cm-by-10 cm

[i.e. length by width]

Area of rectangle = length x width

⇒ Area of rectangular garden = 25 x 10 = 250 square centimeter .

Area required by each flower =  1 square centimeter

Then, the number of flowers they can plant = \dfrac{\text{Area of garden}}{\text{Area of needed by each flower}}

=\dfrac{250}{1}=250

Hence, they can plant 250 flowers.

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Gretchen rode her snowmobile 1 1/4 miles to a snowmobile trail. She rode on the trail for 5 5/6 miles and then rode back home. W
allsm [11]

Answer:

6 18/12 OR simplified  1 6/12

Step-by-step explanation:

1 1/4 + 5 5/6=

1 + 5 = 6

5/6 + 1/4

Mulitipy fraction by 3 and 2

15/12 + 3/12 = 18/12

18/12 = 1 6/12

5 0
3 years ago
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What is the sum of the first 10 terms of the sequence defined by an=3n-3?
netineya [11]
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3 years ago
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the scale from a square park to a drawing of the park is 5 m to 1 cm the actual park has an area of 1,600 m² what is the area of
ludmilkaskok [199]

Answer:

<h2>64 cm²</h2>

Step-by-step explanation:

given:

the scale from a square park to a drawing of the park is 5 m to 1 cm

the actual park has an area of 1,600 m²

find:

what is the area of the drawing of the park​

solution:

drawing scale is 5m : 1cm

<u>1,600 m² </u> = <u>      5² m²  </u>    

   x                  1² cm²

cross multiply:

5² m² x = 1600 m² (1 cm²)

x =<u> 1600 m² </u>

      5² m²

x = 64 cm²

therefore, the area of a square park in the drawing is 64 cm²

5 0
3 years ago
(4). Simplifying polynomials, help pls:) brainliest involved
Roman55 [17]

Answer:

Explanation:

To simplify a polynomial, we have to do two things: 1) combine like terms, and 2) rearrange the terms so that they're written in descending order of exponent.

First, we combine like terms, which requires us to identify the terms that can be added or subtracted from each other. Like terms always have the same variable (with the same exponent) attached to them. For example, you can add 1 "x-squared" to 2 "x-squareds" and get 3 "x-squareds", but 1 "x-squared" plus an "x" can't be combined because they're not like terms.

Let's identify some like terms below.

f(x)=−4x+3x2−7+9x−12x2−5x4

Here you can see that -4x and 9x are like terms. When we combine (add) -4x and 9x, we get 5x. So let's write 5x instead:

f(x)=5x+3x2−7−12x2−5x4

Let's do the same thing with the x-squared terms:

f(x)=5x+3x2−7−12x2−5x4

f(x)=5x−9x2−7−5x4

Now there are no like terms left. Our last step is to organize the terms so that x is written in descending power:

f(x)=−5x4−9x2+5x−7

Step-by-step explanation:

5 0
3 years ago
Plot the point (−12, −52) on the coordinate plane.
irinina [24]

Answer:

Step-by-step explanation:

-12 goes on the x axis (the line that goes ⇄), and because it's negative, it will go to the right.

start from that point (-12 on the x axis) and start going down till you reach -52 on the y axis (the line that goes ⇅)

so it should end up in the bottom left part of the graph

3 0
3 years ago
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