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OverLord2011 [107]
3 years ago
5

Adam has 16.45 kg of flour,and he uses 6.4 kg to make hot cross buns. The remaining flour is exactly enough to make 15 batches o

f scones. How much flour, on kg, will be in each batch of scomes?
Mathematics
2 answers:
suter [353]3 years ago
8 0
16.45 - 6.4 = 10.05

10.05 / 15 = 0.67 kg in each batch
rewona [7]3 years ago
5 0

If Adam has 16.45 kg of flour and he uses 6.4 kg to make hot cross buns, then he has left

16.45 - 6.4 = 10.05 kg of flour.

If Adam wants to use the remaining flour to make 15 batches of scones, then each batch of scones requires

10.05 : 15 = 0.67 kg of flour.

Answer: each batch of scones requires 0.67 kg of flour.

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Question 1 options:Residents in Portland, Oregon think that their city has more rainfall than Seattle, Washington. To test this
dimaraw [331]

Answer:

There is no enough evidence to to support the claim that Portland has more average yearly rainfall than Seattle.

Being μ1: average rainfall in Portland, μ2: average rainfall in Seattle, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 > 0

P-value = 0.1290

As the P-value is bigger than the significance level, the effect is not significant and the null hypothesis failed to be rejected.

Step-by-step explanation:

We have to test the hypothesis of the difference between means.

The claim is that Portland has more average yearly rainfall than Seattle.

Being μ1: average rainfall in Portland, μ2: average rainfall in Seattle, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 > 0

The significance level is 0.10.

The sample for Portland, of size n1=45, has a mean of M1=37.50 and standard deviation of s1=1.82.

The sample for Seattle, of size n1=35, has a mean of M1=37.07 and standard deviation of s1=1.68.

The difference between means is:

M_d= M_1-M_2=37.50-37.07=0.43

The standard error for the difference between means is:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1.82^2}{45}+\dfrac{1.68^2}{35}}=\sqrt{ 0.0736+0.0688 }=\sqrt{0.1424}\\\\\\s_{M_d}=0.3774

We can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.43-0}{0.3774}=1.1393

The degrees of freedom are:

df=n1+n2-2=45+35-2=78

Then, the p-value for this one-tailed test with 78 degrees of freedom is:

P-value=P(t>1.1393)=0.1290

As the P-value is bigger than the significance level, the effect is not significant and the null hypothesis failed to be rejected.

There is no enough evidence to to support the claim that Portland has more average yearly rainfall than Seattle.

7 0
3 years ago
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sukhopar [10]

Add the 2 equations together

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y  =3x+1

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divide by 2

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y = x+1

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=======    add these two equations together

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Answer:

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Step-by-step explanation:

h = 50 m

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slamgirl [31]

Answer:

That is true. More information below.

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6 0
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