They arent congruent when you look at the side lengths and area
This question is incomplete, the complete question is;
In a survey, 55% of the voters support a particular referendum. If 40 voters are chosen at random,
find the mean and variance for the number of voters who support the referendum.
Answer:
a) The Mean is 22
b) Variance is 9.9
Step-by-step explanation:
Given that;
55% of the voters support a particular referendum p = 0.55
q = 1 - p = 1 - 0.55 = 0.45
sample size n = 40
a)
Mean = sample size n × p
Mean = 40 × 0.55
Mean = 22
Therefore the Mean is 22
b)
Variance = n × p × q
so we substitute
Variance = 40 × 0.55 × 0.45
Variance = 9.9
Therefore the Variance is 9.9
Vector QP= (-5+6, 11-4) = (1, 7)
its magnitude is QP= sqrt( 1 + 49)= sqrt (50)=5sqrt2
Answer:
Domain: 1, 6
Range: 4
Step-by-step explanation:
The Domain is the first coordinate which is x
The Range is the second coordinate which is y
Hope This Helps :)
Answer:
a. 38
b. 374
Step-by-step explanation:
a. 2 ft = 24 in + 5 in+ 9 in = 38 in
b. 4 yd = 144 + 6 yd = 216
144 + 216 + 8 + 6 = 374
Hope this helps!
