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docker41 [41]
3 years ago
10

G i rlco me onnyh-wjuv-uwh​

Mathematics
1 answer:
zzz [600]3 years ago
5 0

Answer:

no

Step-by-step explanation:

no one wants to join♥ we dont wanna be sexualized♥

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What are the solutions to the quadratic equation below? X^2-8x+16
leva [86]

(₋4)²

how i got it -

1st i used the sum-product pattern

x² - 8x + 16

x² -4-4+16

then, found the common fact from the two pairs

x² - 4 - 4 + 16

(-4) - 4(-4)

rewrite in factored form

(x-4)-4(-4)

(-4) (-4)

combine to a square

(-4) (-4)

4 0
3 years ago
Read 2 more answers
Help please! i don’t understand how to do this!
atroni [7]

Answer:

x=c+b/a

Step-by-step explanation:

ax-b=c

    +b +b

ax=c+b

__ ___

a=c+b/a

4 0
3 years ago
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. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an
Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when X = 59.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{59.5 - 56}{1.12}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0
3 years ago
If x=9, what is the value of your in the equation below? y=8x-(1+4x)
Phantasy [73]
Y=72-(1+36)
Y=72-37
Y=35
5 0
2 years ago
Read 2 more answers
What is the radical form of the expression (2x^4y^5)^3/8
s344n2d4d5 [400]

We are given expression: (2x^4y^5)^{3/8}

Let us distribute 3/8 over exponents in parenthesis, we get

(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})

= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )

We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.

So, we could write it as.

(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )

Now, we could write inside expression of parenthesis in radical form.

xy\sqrt[8]{2x^{3}x^4y^7}

8 0
3 years ago
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