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3 years ago

G i rlco me onnyh-wjuv-uwh

Mathematics

1 answer:

zzz [600]3 years ago

5 0

Answer:

Step-by-step explanation:

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Through: (-3,0), perp. to y = 3x - 1

Marrrta [24]

Answer:

$y=-\dfrac{1}{3}x-1$

Step-by-step explanation:

Given:

line y=3x-1

point (-3,0)

Write: equation of the line that is perpendicular to the given and passes through the point (-3,0)

Solution:

The slope of the given line is $m=3$

If $m_1$ is the slope of perpendicular line, then

$m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-\dfrac{1}{3}$

So, the equation of the needed line is $y=-\dfrac{1}{3}x+b.$

Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

$0=-\dfrac{1}{3}\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-\dfrac{1}{3}x-1$

7 0

3 years ago

A number divided by 5

viva [34]

10 or 25 and a lot more pretty much anything that ends with 0 or 5

6 0

4 years ago

Eli ran 3/4 of a mile. Every 1/8 of a mile, he jumped over a hurdle. There was a final hurdle at the 3/4 mile park. How many hur

agasfer [191]

Divide 3/4 by 1/8 and you should get 6 hurdles.

5 0

3 years ago

A quadratic equation is shown below:

sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

$3x^{2}-11x+10=0$ has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

$\frac{d}{dx}(3x^{2}-11x+10)=6x-11$

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

$x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

$x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}$

6 0

3 years ago

2/3x + 1/6 = -3/4 x + 1

Marta_Voda [28]

Multiply all terms by 12/1 to get rid of fractions.
8x+2= -9x+12

Add 9x to both sides
17x+2=12

Subtract 2 from both sides
17x=10

Divide both sides by 17
x=10/17

Final answer: x=10/17

8 0

3 years ago

G i rlco me onnyh-wjuv-uwh​

G i rlco me onnyh-wjuv-uwh