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satela [25.4K]
3 years ago
15

What is the volume of this aquarium?

Mathematics
2 answers:
8090 [49]3 years ago
6 0
Volume is length x width x height so 24 x 12 x 18 is your answer
bekas [8.4K]3 years ago
6 0

4224 in^3

24*12*18 - 10*8*12

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I need help ASAP please and thank you
Pavel [41]

9514 1404 393

Answer:

  C. 4 +√(x+5)

Step-by-step explanation:

The sign between the terms changes to form the conjugate. The radical contents are unchanged.

The conjugate of 4 -√(x+5) is 4 +√(x+5).

_____

<em>Additional comment</em>

The utility of a conjugate is that the product of a number and its conjugate is the difference of two squares. The squares are intended to remove an undesirable feature of the number, its imaginary part or its irrational part, for example. Here, the product of the number and its conjugate would be ...

  (a -b)(a +b) = a² -b²

  4² -(√(x+5))² = 16 -(x +5) = 11 -x . . . . no longer contains a root

7 0
3 years ago
HOW DO YOU DO THIS? PLEASE SHOW WORK ASAP!
MrMuchimi
2. m<-1.5
3. 11≥x
4. x≥1
5. x≥2

5 0
3 years ago
Read 2 more answers
Logan has a budget of $400 to have family pictures taken. There is a sitting fee of $38. Prints cost $25 per page. How many page
fredd [130]

Answer:

14

Step-by-step explanation:

400-38=362

362/25=14.48

Logan can only print 14 whole pages.

5 0
4 years ago
Read 2 more answers
(15 Points)
expeople1 [14]

ANSWER 1



Note that,


f(u)=tan^{-1}(u)


is the same as


f(u)=arctan(u)



We apply the product rule.


f(x)=x^2tan^{-1}(x)


So we keep the second function and differentiate the first,plus we keep the first function and differentiate the second.


f'(x)=(x^2)'tan^{-1}(x)+x^2(tan^{-1}(x))'



Recall that,

If

f(u)=tan^{-1}(u)



Then,

f'(u)=\frac{1}{1+u^2}} \times u'


This implies that,

f'(x)=2xtan^{-1}(x)+\frac{x^2}{x^2+1}



ANSWER 2


We apply the product rule and the chain rules of differentiation here.



f(x)=xsin^{-1}(1-x^2)




f'(x)=x'sin^{-1}(1-x^2)+x(sin^{-1}(1-x^2))'



Recall that,

If

f(u)=sin^{-1}(u)



Then,

f'(u)=\frac{1}{\sqrt{1-u^2}} \times u'



This implies that,


f'(x)=sin^{-1}(1-x^2)+x \times \frac{1}{\sqrt{1-(1-x^2)^2}}\times (-2x)


f'(x)=sin^{-1}(1-x^2)-\frac{2x^2}{\sqrt{1-(1-2x^2+x^4)}}


f'(x)=sin^{-1}(1-x^2)-\frac{2x^2}{\sqrt{1-1+2x^2-x^4}}



f'(x)=sin^{-1}(1-x^2)-\frac{2x^2}{\sqrt{2x^2-x^4}}





5 0
4 years ago
If Josh has 27 ballons at his b-day party and 12 of them float away, how many ballons does Josh have left? 15
Vinil7 [7]
Yes, that is the correct answer. 27-12=15
6 0
2 years ago
Read 2 more answers
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