Answer:
45 degrees
Step-by-step explanation:
Think of it like this the sum of the angles in a triangle are the always the same 180 degrees.
So now, we do 180 - 90 = 90 this is the sum of the other angles.
We shall assume that they are the same and divide 90/2 = 45 degrees each
Ok here are some things to understand while solving!
- If three sides of one triangle are equal to three sides of another triangle, the triangles are congruent.
- If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.
- If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.
- If two angles and the non-included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.
- If the hypotenuse and one leg of one right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle, the two triangles are congruent.
- Without knowing at least one side, we can't be sure if two triangles are congruent. (which we do!)
Hope this helped!
Study hard!
Answer:
$2.51
Step-by-step explanation:
12.55/5= 2.51
a bag of dog treats is 2.51 per bag
When we factorise an expression, we are looking for simple factors that multiply to get the original expression. Usually it is very natural to factorise something like a quadratic in x. For example:
x^2 + 3x + 2 = (x+1)(x+2)
But there are other situations where factorisation can be applied. Take this quadratic:
x^2 - 9x = x(x-9)
This second example is closer to the question in hand. Just like x was a common factor to both x^2 and -9x, we are looking for a common factor to both 6b and 24bc. The common factor is 6b.
Hence 6b + 24bc = 6b(1 + 4c).
I hope this helps you :)
Suppose
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is the number of possible combinations for a suitcase with a lock consisting of

wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for

wheels, or

is given recursively by the formula
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starting with
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(because you can start the combination with any one of the ten available digits 0 through 9).
For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).
By substitution, you have

This means a lock with 55 wheels will have

possible combinations (a number with 53 digits).
Answer:
A. Gasoline
Step-by-step explanation: