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elixir [45]
3 years ago
5

Can someone explain inequality using a word problem

Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0
What is the inequality between these two fractions 1/2 2/4: answer =...so you would write it out like this 1/2=2/4
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Which of the following is the accurate APA format for writing out the bragger condition main effect result for the willingness o
Rama09 [41]

Answer:

First, the main effect for bragger condition is significant because F statistic is F(1,116) = 68.65 with p value = 0.000, which is less than 0.001

mean and standard deviation for truthful Bragger condition are 6.83 and 1.14

mean and standard deviation for untruthful Bragger condition are 5.80 and 0.82

So, it is clear that the Edward was more likeable in the Truthful Bragger condition.

Therefore, option D is answer

5 0
3 years ago
Verify that f and g are inverses functions using composition , show your steps
pshichka [43]

Answer:

See explanations below

Step-by-step explanation:

Given the functions

f(x) = 12x - 12

g(x) = x/12 - 1

To show they are inverses, we, must show that f(g(x)) = g(f(x))

f(g(x)) = f(x/12 - 1)

Replace x with x/12 - 1 into f(x)

f(g(x)) =12((x-12)/12) - 11

f(g(x)) =  x-1 - 1

f(g(x)) =x - 2

Similarly for g(f(x))

g(f(x)) = g(12x-12)

g(f(x)) =(12x-12)/12 - 1

12(x-1)/12 - 1

x-1 - 1

x - 2

Since f(g(x)) = g(f(x)) = x -2, hence they are inverses of each other

5 0
3 years ago
I need help asap....................
docker41 [41]

Based on the given points, the point that is located on the y-axis is (0,7).

<h3>Which point is on the y axis?</h3>

The point that is on the y-axis should have a coordinate such that x is equal to 0.

This leads to the point being on the y-axis because the nonzero coordinate of the y axis would then have to be placed on the same axis.

The only point with a 0 coordinate is (0, 7) so this is the point that is located on the y-axis.

Find out more on points on the y-axis at brainly.com/question/4656315

#SPJ1

7 0
2 years ago
Which of the following methods can be used to find the derivative of y = arcsin x with respect to z ?
vfiekz [6]

Answer:

B) Ill only

Step-by-step explanation:

This is because y = arcsin x can be re-written as sin y = x, We then differentiate sin y = x implicitly with respect to z to obtain

d(siny)/dz = dx/dz

(cosy)dy/dz = dx/dz

dy/dz = (1/cosy)dx/dz

5 0
2 years ago
Find an equation of the plane. the plane through the point (−5, 9, 10) and perpendicular to the line x = 1 + t, y = 4t, z = 2 −
PtichkaEL [24]
The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.

Since the plane passes through point (-5,9,10), the required plane is :
&Pi; 1(x-(-5)+4(y-9)-3(z-10)=0
=>
&Pi; x+4y-3z=1

3 0
3 years ago
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