Answer:
Equation: 3x + 2 = 50
# of friends: 16
Step-by-step explanation:
3 chocolates each or 3x because what "each" means is not known yet-
3x
<em>Note: Always use x for an unknown value</em>
2 remaining chocolates-
3x + 2
50 total chocolates-
3x + 2 = 50
Remove two to keep the x alone-
3x = 48
Remove the 3 or the "Coefficient" by dividing-
48/3 = 16
x = 16
Equation: 3x + 2 = 50
# of friends: 16
In geometry, it would be always helpful to draw a diagram to illustrate the given problem.
This will also help to identify solutions, or discover missing information.
A figure is drawn for right triangle ABC, right-angled at B.
The altitude is drawn from the right-angled vertex B to the hypotenuse AC, dividing AC into two segments of length x and 4x.
We will be using the first two of the three metric relations of right triangles.
(1) BC^2=CD*CA (similarly, AB^2=AD*AC)
(2) BD^2=CD*DA
(3) CB*BA = BD*AC
Part (A)
From relation (2), we know that
BD^2=CD*DA
substitute values
8^2=x*(4x) => 4x^2=64, x^2=16, x=4
so CD=4, DA=4*4=16 (and AC=16+4=20)
Part (B)
Using relation (1)
AB^2=AD*AC
again, substitute values
AB^2=16*20=320=8^2*5
=>
AB
=sqrt(8^2*5)
=8sqrt(5)
=17.89 (approximately)
Answer:
f(2)-f(1) => Difference between the count of bacteria between 11AM and 10AM
Step-by-step explanation:
Here x is the number of hours after 9AM
f(2) means the count of bacteria after 2 hours of 9AM i.e. at 11AM
f(1) means the count of bacteria after 1 hour of 9AM i.e. at 10 AM
f(2) - f(1) will give us the difference between the count of bacteria between 11 AM and 10 AM
Hence,
f(2)-f(1) => Difference between the count of bacteria between 11AM and 10AM
Answer: C
The x row goes up every time by two and the y decreases by 4.
6-4=2 ect...
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