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Licemer1 [7]
2 years ago
13

-5(x+2y)+15(x+2y);x7and y=-7

Mathematics
1 answer:
Nat2105 [25]2 years ago
6 0
I believe your answer should be 105x squared-1475x+70
sorry i'm not really sure how to put the little two above the first x but my answer is mathematically correct.
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Rewrite the expression in the form
kodGreya [7K]
In Exponential form 2(X x 4x^-5/2)^1/2
3 0
2 years ago
Find the complex fourth roots of 81(cos(3π/8)+isin(3π/8)). a) Find the fourth root of 81. b) Divide the angle in the problem by
WARRIOR [948]

Answer:

The answer is below

Step-by-step explanation:

Let a complex z = r(cos θ + isinθ), the nth root of the complex number is given as:

z_1=r^{\frac{1}{n} }(cos(\frac{\theta +2k\pi}{n} )+isin(\frac{\theta +2k\pi}{n} )),\\k=0,1,2,.\ .\ .,n-1

Given the complex number z = 81(cos(3π/8)+isin(3π/8)), the fourth root (i.e n = 4) is given as follows:

z_{k=0}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(0)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(0)\pi}{4} ))=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})] \\z_{k=0}=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})]\\\\z_{k=1}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(1)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(1)\pi}{4} ))=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})] \\z_{k=1}=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})]\\\\

z_{k=2}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(2)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(2)\pi}{4} ))=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})] \\z_{k=2}=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})]\\\\z_{k=3}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(3)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(3)\pi}{4} ))=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})] \\z_{k=3}=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})]

3 0
3 years ago
What is twenty six times thirty seven
insens350 [35]
Twenty six times thirty seven is 962
6 0
3 years ago
Hi can anybody explain to me how to do this I'm kinda confused . 5×[5(-7)]​
telo118 [61]

Answer:

5 × [5(-7)]

= 5 × (-35)   ---- 5 × (-7) = -35

= -175

4 0
3 years ago
Add 3/14+4/14 simply your answer
Mila [183]

Answer:

\Large \boxed{\frac{1}{2}}

Step-by-step explanation:

\displaystyle \frac{3}{14} +\frac{4}{14}

Add the fractions since the denominators are the same.

\displaystyle \frac{3+4}{14}

\displaystyle \frac{7}{14}

Simplifying the fraction.

\displaystyle \frac{7(1)}{7(2)}

\displaystyle \frac{1}{2}

5 0
2 years ago
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