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astra-53 [7]
2 years ago
10

The lines shown below are perpendicular. If the green line has a slope of 2/5 what is the slope of the red line

Mathematics
1 answer:
Ksenya-84 [330]2 years ago
6 0
In this item, we are not given with the figure but knowing that these lines ought to be perpendicular then we will be able to derive the relationship between the slopes of the line. 

The slopes of the perpendicular line are the negative reciprocals of one another. If we represent the slopes of the lines as m₁ and m₂, the relationship can be written in the form,
           (m₁)(m₂) = -1

We are given with one of the slopes. To determine the value of the second slope then,
            m₂ = -1/m₁
            m₂ = -1/(2/5)
            m₂ = -5/2

<em>ANSWER: m₂ = -5/2</em>
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KonstantinChe [14]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
(x-4)/5=9-(2x-41)/9
jok3333 [9.3K]
For this question, you have to take Least Common Multiplier for which in this case will be "45" as, the denominators can get similar and get multiplied by a same value to form a similar expression. This allows us to cancel out them by common factors. Full process shown below.

\mathbf{Given \: \: Expression: \: \dfrac{x - 4}{5} = 9 - \dfrac{2x - 41}{9}}

\mathbf{\dfrac{x - 4}{5} \times 45 = 9 \times 45 - \dfrac{2x - 41}{9} \times 45}

\mathbf{9(x - 4) = 405 - 5 (2x - 41)}

\mathbf{9x - 36 = 405 - 10x + 205}

\mathbf{9x - 36 = - 10x + 610}

\mathbf{9x - 36 + 36 = - 10x + 610 + 36}

\mathbf{9x = - 10x + 646}

\mathbf{9x + 10x = - 10x + 646 + 10x}

\mathbf{19x = 646}

\mathbf{\dfrac{19x}{19} = \dfrac{646}{19}}

\mathbf{\therefore \quad x = 34}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is; \: \: x = 34}}}

Hope it helps.
3 0
2 years ago
Need help failing math
faust18 [17]

Answer:

6,-9

Step by step explaination

<em><u>First</u></em><em><u> </u></em><em><u>yo</u></em><em><u>u</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>got</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>(</u></em><em><u>4</u></em><em><u>-</u></em><em><u>7</u></em><em><u>)</u></em>

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8 0
2 years ago
Read 2 more answers
Using triangle A B C as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a
Ostrovityanka [42]

Answer:

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

<em>Hence the coordinate point which is not a coordinate of dilation is:</em>

<em>begin ordered pair 4 comma 12 end ordered pair  i.e. (4,12)</em>

3 0
3 years ago
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suter [353]

Answer:

-81 - y

Step-by-step explanation:

To simplify the expression -3[2-(y-5)]-4[3(y+1)-(6-y)(-2)] use order of operations or PEMDAS.

-3[2-(y-5)]-4[3(y+1)-(6-y)(-2)]

-3[2-y+5]-4[3y + 3+12 -2y]

-3[7-y] -12y-12-48+8y

-3[7-y] - 4y - 60

-21 + 3y - 4y - 60

-81 - y

5 0
3 years ago
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