Answer:
See below.
Step-by-step explanation:
2b + 8 − 5b + 3 = −13 + 8b − 5
Reorder like terms.
2b-5b+8+3=8b-13-5
Combine those like terms. Then solve.
-3b+11=8b-18
-11 -11
-3b=8b-29
-8b -8b
-11b=-29
/-11 /-11
b=2.64
-hope it helps
The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
<em><u>Solution:</u></em>
Given the statement:
Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen
Let us first understand the given statement,
Let the number be "x"
" sum of a number and four" means x + 4
"Three sets of a sum of a number and four" translated to 3(x + 4)
"sum of seven times the same number and thirteen" means 7x + 13
<em><u>Thus the algebraic expression for given statement is:</u></em>

<em><u>Using distributive property in above expression</u></em>

Therefore,

<em><u>Combine the like terms</u></em>

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
The rectangle is 15cm by 45cm
2(3x)+2(x)=120
6x+2x=120
8x=120
X=15
3(15)=45
Answer:
330.88 m/min
Step-by-step explanation:
rate = distance/time
= 4000 /12.089
= 330.88 m/min
Answer:
The sample size required is, <em>n</em> = 502.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion is:

The margin of error is:

Assume that 50% of the people would support this political candidate.
The margin of error is, MOE = 0.05.
The critical value of <em>z</em> for 97.5% confidence level is:
<em>z</em> = 2.24
Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B2.24%5Ctimes%20%5Csqrt%7B0.50%281-0.50%29%7D%7D%7B0.05%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D501.76%5C%5C%5C%5C%5Capprox%20502)
Thus, the sample size required is, <em>n</em> = 502.