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soldi70 [24.7K]
3 years ago
13

At a garage sale, damaged paperback books sell for 40 cents each. Books with minor damage sell for 50 cents each and undamaged b

ooks sell for 80 cents each. A customer decides to spend the same amount of money on each type of book. What is the least amount possible the customer will spend on undamaged books?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
7 0
Ok....we need lowest common multiple of 0.40, 0.50, 0.80...and that is gonna be : 4.00......so the customer spends $ 4.00
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Please help!!!
Ratling [72]

x = 3

2x + y - z = 3 → (1)

- x + y + 2z = 0 → (2)

3x + 2y + z = 9 → (3)

we require to eliminate the y and z terms from the equations

(1) + (3) : 5x + 3y = 12 → (4)

multiply (1) by 2

4x +2y - 2z = 6 → (5)

(2) + (5) : 3x + 3y = 6 → (6)

(4) - (6) : 2x = 6 ⇒ x = 3


8 0
3 years ago
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valkas [14]
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6 0
2 years ago
1. William earns $134,644.80 per year, and has his federal taxes withheld from each weekly check. In addition, a total of $53.60
SashulF [63]
I only have the answer for 3 and i believe it is 20,090

3 0
2 years ago
Please help me it’s a formative grade
sergejj [24]

Answer:

Step-by-step explanation: 800/x=100/17

(800/x)*x=(100/17)*x       - we multiply both sides of the equation by x

800=5.88235294118*x       - we divide both sides of the equation by (5.88235294118) to get x

800/5.88235294118=x

136=x

x=136

83% of 800=664

5 0
3 years ago
Solve the equation<br> 5х + 8 – 3x = -10<br><br> x=-9<br> x=-1<br> x=1<br> x= 9
enyata [817]
The answer is -9. Have a great day
4 0
2 years ago
Read 2 more answers
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