Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Write a number with the digit 8 in the tens place
1 answer:
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Let's start with the easier points, the x-intercepts (5, 0) and (-1, 0).
Since this hyperbola has two x-intercepts, we're dealing with a horizontal hyperbola, and the center is the midpoint between the x-intercepts.
The center coordinates are (2, 0), then, our equation is
To find the missing coefficients, we can just substitute the remaining points and solve the system for a and b. Our final equation is