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3 years ago

Can i have help please. Step by step

Mathematics

2 answers:

nignag [31]3 years ago

6 0

Answer: It's in the step-by step explanation

Step-by-step explanation:

I just learned about this too. I'll use what I know to help you out.

According to whatever law of the circle, where you have two intersecting lines within the bounds of a circle(that'd be TQ and SW), the product of the divided segments will equal each other.

So to put that in terms, TU times QU = SU times WU.

So let's get the value of segment TU, which is 1.5

Then let's get the value of segment of QU, which is 4.

Now let's get the value of WU, which is 3. We don't know what SU is yet. So put it in algebraic form.

1.5(4)=3x

6=3x

2=x

bon appetit

MA_775_DIABLO [31]3 years ago

5 0

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point s has coordinates 2,5 if you rotate point s 90 degrees about the origin 0,0 what are the coordinates of s

Volgvan

The answer is 2,-5 you put the points are in the same spot just rotated

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3 years ago

Solve for x 2(x-3)+5=4-7(2x-1) A. -1/10 B. 3/4 C. 1/2 D. 1/16

Stolb23 [73]

Hello
2(x-3)+5=4-7(2x-1)
2x-6+5 = 4 -14x+7
2x+14x =6-5+4+7
16x=12
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x=(4×3)/(4×4)
x=3/4 (simplified by 4)
answer B

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3 years ago

Read 2 more answers

Conti. 7-10 thanks a lot! unhelpful answers will be deleted.

Marysya12 [62]

Answers:

10. b. $\displaystyle 13$

9. b. $\displaystyle 20$

8. a. $\displaystyle 33$

7. a. $\displaystyle 25°$

Step-by-step explanations:

10. Both segments are considered congruent, so turn both expressions into an equation:

$\displaystyle 3x - 5 = x + 7 \hookrightarrow \frac{-12}{-2} = \frac{-2x}{-2} \\ \\ 6 = x$

Plug this back into the equation to get $\displaystyle 13$ on both sides.

9. All edges in a square obtain congruent right angles and edges, so set $\displaystyle 45$ equivalent to the given expression:

$\displaystyle 45 = 2x + 5 \hookrightarrow \frac{40}{2} = \frac{2x}{2} \\ \\ \boxed{20 = x}$

8. Both angles are considered supplementary, so turn both expressions into an equation and set it to one hundred eighty degrees:

$\displaystyle 180 = (4x - 15)° + (x + 30)° \hookrightarrow 180° = (15 + 5x)° \hookrightarrow \frac{165}{5} = \frac{5x}{5} \\ \\ \boxed{33 = x}$

7. In this rectangle, segment EO is a segment bisectour, making these angles Complementary Angles. Therefore, set an equation up to find its complement:

$\displaystyle 90° = 65° + m\angle{VOE} \\ \\ \boxed{25° = m\angle{VOE}}$

I am joyous to assist you at any time.

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2 years ago

Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has

Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0), Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

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3 years ago