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defon
3 years ago
6

Choose the point-slope form of the equation below that represents the line that passes through the point (−1, 6) and has a slope

of −3. A.y − 6 = −3x − 3 B.y − 6 = −3(x + 1) C.y = −3x + 3 D.3x + y = 3
Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
Point slope form of the equation can be written as follows
y - y₁ = m (x - x₁)
y and x are the 2 variables , m is the slope and x₁ and y₁ are the respective coordinates for the given point
in this format a point of a line and the slope of the line are given. using this information we can write down the point - slope formula for the graph
since a point has been given we know the x₁ and y₁ coordinates.
These are the coordinates of the given point (-1,6)
x₁ = -1
y₁ = 6
slope has been given as -3, m = -3
substituting these values in the formula, 
y - y₁ = m (x - x₁)
y - 6 = -3 (x - (-1))
y - 6 = -3 (x + 1)
answer is B.

IrinaVladis [17]3 years ago
3 0

Answer:

The correct answer is option B.

Step-by-step explanation:

Two point form of the equation:

(y-y_1)=\frac{y_2-y_1}{x_2-x_1}\times (x-x_1)

\frac{y_2-y_1}{x_2-x_1}=Slope=m

(y-y_1)=m\times (x-x_1)

A line passing through the point (-1,6) with slope ,m = -3.

The equation of the line will be:

y-6=(-3)(x-(-1))=(-3)(x+1)

Hence, the correct answer is option B.

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elena-14-01-66 [18.8K]

Answer:

m∠3 = 49°

Step-by-step explanation:

From the picture attached,

lines m and n are the parallel lines and line t is a transversal line intersecting these parallel lines at E and B respectively.

Therefore, ∠DEF ≅ ∠ABC [Exterior alternate angles]

m∠1 + m∠2 = m∠4 + m∠5

m∠4 = m∠5 [line s bisects ∠ABC]

50° + 48° = m∠4 + m∠4

98° = 2m∠4

m∠4 = 49°

Since, ∠4 ≅ ∠3 [Vertically opposite angles]

m∠3 = 49°

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Step-by-step explanation:

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