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IceJOKER [234]
3 years ago
11

The chart gives three different international calling plans. Jamie has budgeted $20 per month for international calls. Round ans

wers to the nearest minute. Plan Monthly Fee Charge per minute A $3.95 $0.08 B $8.95 $0.06 C $0 $0.10 1. How many minutes will Jamie be able to use per month with Plan A? 2. How many minutes will Jamie be able to use per month with Plan B? 3. How many minutes will Jamie be able to use per month with Plan C? 4. Nolan has allowed $50 per month for long distance. Which plan is best deal for Nolan's budget?
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0
A. 200.625 minutes   B. 184.166 minutes  C. 200 minutes  (round these answers like the question asked) 4. Plan A is the best because you get the most minutes for your money. I will explain my work for A, but if you need to explain the rest just ask. So, if you have to pay $3.95 every month no matter what and $0.08 for every minute you talk you can write the equation as, Cost = 3.95 + 0.08m (m stands for minutes), and the cost is 20$ then the equation is 20 = 3.95 + 0.08m, subtract 3.95 from the right side to make it 16.05 = 0.08m, then divide everything by 0.08 to get m, which gives you m= 200.625 
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This graph represents a quadratic function. What is the function’s equation written in factored form and in vertex form?
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Answer:

\textsf{Factored form}: \quad f(x)=2x(x-4)

\textsf{Vertex form}: \quad f(x)=2(x-2)^2-8

Step-by-step explanation:

<u>Factored form of a quadratic function</u>

f(x)=a(x-p)(x-q)

where:

  • p and q are the x-intercepts
  • a is some constant

Given x-intercepts:

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Therefore:

\implies f(x)=a(x-0)(x-4)

\implies f(x)=ax(x-4)

To find a, substitute the given vertex (2, -8) into the equation and solve for a:

\implies 2a(2-4)=-8

\implies -4a=-8

\implies a=2

Therefore, the function's equation in factored form is:

f(x)=2x(x-4)

<u>Vertex form of a quadratic equation</u>

<u />f(x)=a(x-h)^2+k

where:

  • (h, k) is the vertex
  • a is some constant

Given:

  • vertex = (2, -8)

Therefore:

\implies f(x)=a(x-2)^2-8

To find the constant a, substitute one of the x-intercepts into the equation and solve for a:

\implies a(0-2)^2-8=0

\implies 4a-8=0

\implies a=2

Therefore, the function's equation in vertex form is:

f(x)=2(x-2)^2-8

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Answer:

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