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4 years ago

The graph of an absolute value function opens up and has a vertex of (0, -3).

Mathematics

1 answer:

lutik1710 [3]4 years ago

4 0

Answer:

domain (-∞, ∞)

range [-3,∞)

Step-by-step explanation:

domain is the x value and range is the y value. Since its an absolute value the y value rises from both sides of the x value in a 45° angle.

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Please help with inequalities and exponentials

zlopas [31]

Answer:

A.b ≤ 40

Step-by-step explanation:

Janice weighs 130 pounds so you must take away his weight from the weight limit (250 pounds). That will give you 120. 120 pounds can still be put on the truck. Since each block weighs 3 pounds, you have to divide 120 divided by 3, giving you 40. Janice can carry up to 40 blocks on the truck each trip.

7 0

3 years ago

Multiply. 35⋅34 A. 920 B.410 C. 45 D. 54

Anni [7]

Answer: 1190

None of these answer choices are correct I showed my work on paper.

8 0

3 years ago

Help me with this .

vaieri [72.5K]

Open circle at -1 pointing left and closed circle at 2 pointing right

4 0

3 years ago

Read 2 more answers

What is the equation of the line that is perpendicular to the given line and passes though the point (3,0)? ......What is the an

Stolb23 [73]

Answer: The correct option is (D) $5x-3y=15.$

Step-by-step explanation: We are given to find the equation of a line that is perpendicular to the graphed line and passes through the point (3, 0).

From the graph, we note that

the graphed line passes through the points (2, -1) and (-3, 2).

The SLOPE of a straight line passing through the points (a, b) and (c, d) is given by

$m=\dfrac{d-b}{c-a}.$

So, the slope of the graphed line is

$m=\dfrac{2-(-1)}{-3-2}\\\\\Rightarrow m=-\dfrac{3}{5}.$

We know that the product of the slopes of two perpendicular lines is -1. So, if m' is the slope of a line perpendicular to the graphed line, then

$m\times m'=-1\\\\\Rightarrow -\dfrac{3}{5}\times m'=-1\\\\\Rightarrow m'=\dfrac{5}{3}.$

Since the line with slope m' passes through the point (3, 0), so its equation will be

$y-0=m'(x-3)\\\\\\\Rightarrow y=\dfrac{5}{3}(x-3)\\\\\Rightarrow 3y=5x-15\\\\\Rightarrow 5x-3y=15.$

Thus, the required equation of the perpendicular line is $5x-3y=15.$

Option (D) is CORRECT.

8 0

4 years ago

The value of 8 in 8596 is blank times the value of 8 in 985

RSB [31]

8 in 8596= 8000
8 in 985=80
8000 divided by 80= 100

3 0

3 years ago