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3 years ago

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Find the value of x

1 answer:

Svetlanka [38]3 years ago

6 0

Answer:

Step-by-step explanation:

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Given the equation Y -3 equals 1/2 (X +6 )in point slope form identify the equation of the same line in standard form

liberstina [14]

The standard form of a line:

$Ax+By=C$

We have the equation of a line in the slope-point form:

$y-3=\dfrac{1}{2}(x+6)$ use distributive property

$y-3=\dfrac{1}{2}x+3$ add 3 to both sides

$y=\dfrac{1}{2}x+6$ multiply both sides by 2

$2y=x+12$ subtract x from both sides

$-x+2y=12$ change the signs

$x-2y=-12$

4 0

4 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

4 years ago

Determine whether y = -2x² - 3 is a function.

Alexus [3.1K]

Answer:yes

Step-by-step explanation:

5 0

2 years ago

Sixty percent (60%) of those who attended the soccer game were parents. There were 120 people who

IrinaVladis [17]

Answer:

72

Step-by-step explanation:

<u>Given:</u>

There were 120 people in total.

60% were parents.

<u>To find:</u>

Number of parents attended.

Solution:

1. 60% of 120

It can also be written as:

$\frac{60}{100}\times \frac{120}{1}$

Simplify

Cancel zeros

$\frac{60}{100}\\\\=\frac{6}{10}$

Divide by common factor (2)

$\frac{6\div2}{10\div2}=\frac{3}{5}$

2. $\bold{\frac{3}{5}\times \frac{120}{1}}$

Multiply

$\frac{3\times120}{5\times1} = \frac{360}{5}$

Divide

$\frac{360}{5}= 360\div5=72$

Therefore, 72 parents attended the game.

4 0

3 years ago

12ad3<br> and which term are like terms?<br><br> 15a3d<br><br> 10ad<br><br> 12d3<br><br> 3ad3

Savatey [412]

Answer: $3ad^3$

Step-by-step explanation:

Given term: $12ad^3$

<em>In algebra, like terms are the terms which have the same variables with same powers. </em>

Here the variables are a and d, where d has power 3.

From the given options $3ad^3$ is the right answers as it has the same variables and power.

Rest of other options are unlike terms to the given term.

7 0

3 years ago

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