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Jlenok [28]
3 years ago
11

Kayla uses fancy beads which she purchases online to make bangle bracelets. The chart shows the number of beads available for di

fferent prices. What is the difference in the unit price for the BEST deal and the unit price for the MOST EXPENSIVE deal?
Mathematics
2 answers:
dezoksy [38]3 years ago
6 0

Answer:B

Step-by-step explanation:

yarga [219]3 years ago
3 0

Answer:2 cent per bead

unit price =

price

quantity

→

$6.00

100

= 6¢ per bead (MOST EXPENSIVE DEAL) →

$10.00

200

= 5¢ per bead →

$16.00

400

= 4¢ per bead (BEST DEAL) →

$30.00

600

= 5¢ per bead →

$55.00

1000

= 5.5¢ per bead

6 cents − 4 cents = 2 ce

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Any help with an explanation would be appreciated!
Lilit [14]

Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)

h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
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3 years ago
Check the picture of the necessary information
denis-greek [22]
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Step-by-step explanation:

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