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faltersainse [42]
3 years ago
13

Write each literal term in exponential form. kkkkknn

Mathematics
1 answer:
hram777 [196]3 years ago
7 0
Good Job Hannamcbrayer1 But for me I would separate them like this so they don't get confused. K^5  N^2. Not trying to bash on you in anyway at all just trying to help you. 
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KJ=3x+12 And KH=6x-15. What is KG?
Andreyy89

Answer:

39


Step-by-step explanation:

3x + 12 = 6x - 15

6x - 3x = 12 + 15

3x = 27

x = 9


KJ = KH = KG = 3x + 12

KG = 3.(9) + 12

KG = 27 + 12

KG = 39


I hope I helped you.

7 0
3 years ago
The sum of two numbers is ten. One number is twenty less than four times the other. Find the numbers
Brut [27]

Answer:

6 and 4

Step-by-step explanation:

Let one number be x.

Then another will be : 4x - 20

In accordance with the question;

x + 4x - 20 = 10

5x = 10 + 20

x = 30/5

= 6

x = 6

4x - 20 = 4×6 - 20 = 4

So, the numbers are 6 and 4.

5 0
2 years ago
Which numbers are solutions to the inequality below?
babunello [35]

Answer:

4, 5 and 6

Step-by-step explanation:

Add 19 to both sides:

-4x > 52

Divide by -4

x > -13 (Flip the sign when multiplying or diving by a negative)

4, 5 and 6 satisfy this

6 0
3 years ago
PLEASE HELP ME FAST! THIS IS A SIMPLE TRIG PROBLEM BUT I SKIPPED CLASS.
NikAS [45]

we can factor the whole thing:

(2sin(x) -1)(sin(x)+1) = 0.

Therefore, sin(x) = -1 and sin(x) = 1/2.

For the first one x = 3π/2 and the second is π/6 and 5π/6

So 3π/2, π/6 and 5π/6 are the solutions.

I do kind of have a problem with this because it doesn't mention if you should go over 360°. Otherwise, you have to add in an 2nπ into the equations like 3π/2 + 2nπ; n \in \mathbb{W}

but I don't know if that is necessary for you.

3 0
3 years ago
Lin runs 5 laps around a track in 6 minutes.
Paladinen [302]

Answer:

25.2

Step-by-step explanation:

6/5 is 1.2, so it takes 1.2 minutes to run one lap.

This means 21 x 1.2 = the minutes it takes to run 21 laps around the track.

Therefore it takes 25.2 minutes to run around the track 21 times.

3 0
3 years ago
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