All categories

3 years ago

Please Help me. . . . . .

Mathematics

2 answers:

ololo11 [35]3 years ago

8 0

Answer:

Step-by-step explanation:

f(x)-g(x)=x²+2x-5+3x²+4x-1 combine like terms

4x²+6x-6

avanturin [10]3 years ago

6 0

Answer:

Step-by-step explanation:

x^2+2x-5-(-3x^2-4x+1)

x^2+2x-5+3x^2+4x-1

4x^2+6x-6

You might be interested in

Together a refrigerator and a desk cost $216. Find the price of each if the refrigerator costs three times as much as the desk

zheka24 [161]

Refrigerator 162$ and desk cost 54

6 0

3 years ago

Read 2 more answers

Cuantas veces cabe el 7 en el 4

SVEN [57.7K]

<span>7 no encaja en 4, por lo que la respuesta sería cero 7 ajustes en 4, cero veces</span>

8 0

3 years ago

Look at the data in the table.

11111nata11111 [884]

Given table

______

x y

______

2.4 9

7.2 28

7 24

8.3 35

3.1 9

7.2 30

9 32

_________

So, the coordinates on the graph (2.4, 9), (7.2, 28), (7, 24), (8.3, 35), (3.1 , 9), ( 7.2, 30), (9, 32).

The first graph represents the line of best fit.

The definition of line of best fit " A line of best fit is a straight line that best represents the data on a scatter plot. This line may pass through some of the points, none of the points, or all of the points.".

<h3>Note: Most of the points should be as closer as possible to the drawn line. </h3>

5 0

3 years ago

Read 2 more answers

How can you isolate the variable x on one side of an inequality

Tcecarenko [31]

you combine like terms first.

for example: 2x=2+5

add up the two plus 5 so that will give you seven then you're going to divide 2 by 7 so that you isolate the x and you'll get your answer.

8 0

3 years ago

Find the area of a rectangle with a length of 5 1/3 inches and a width of 2/3 inch

neonofarm [45]

Step-by-step explanation:

$length \: of \: rectangle \\ l = 5 \frac{1}{3} \: inches = \frac{16}{3} \:inches \\ \\ width \: of \: rectangle \: \\ w = \frac{2}{3} \: inch \\ \\ area \: of \: rectangle \\ = l \times w \\ \\ = \frac{16}{3} \times \frac{2}{3} \\ \\ = \frac{32}{9} \\ \\ \red{ \boxed{ \therefore area \: of \: rectangle = 3 \frac{5}{9} \: {inch}^{2} }}$

4 0

3 years ago