Answer: rectangle.
Step-by-step explanation:
Given points: K(0,0) I(2,2) T(5,-5) E(7,-3)
Distance formula to find distance between and :
i.e. KI = TE and KT= IE, so opposite sides equal.
It can be a parallelogram or rectangle. [if all sides are equal it would be square or rhombus]
IT= KE, i.e. diagonals are equal.
It means KIET is a rectangle.
Answer: The volume of the cylinder is 9,184.5 cubic millimeters.
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Volume of a cylinder (V) : π x radius ² x height
Replacing with the values given and solving for v (Volume)
V = 3.14 x 15² x 13
V = 9,184.5 mm3
In conclusion, the volume of the cylinder is 9,184.5 cubic millimeters.
Feel free to ask for more if needed or if you did not understand something
Answer:
5/6
Step-by-step explanation:
it is already written as a fraction.
do you mean as a decimal???
Answer:
a) Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7
b) The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as
98 square feet
Step-by-step explanation:
The area in, square feet, of Shawn’s garden is found be calculating 15(2x + 7). Shawn incorrectly says the area can also be found using the expression 30x + 7.
The correct area =
15(2x + 7).
= 30x + 105 square feet
The error in Shawn’s expression is
= 15(2x + 7)
= 30x + 7 square feet
Shawn's error was that he Multiplied 15 by 2x only. He didn't Multiply 15 by 7
The difference, in square feet, between the actual area of Shawn’s garden and the area found using his expression is given as
30x + 105 square feet - 30x + 7 square feet
= 30x + 105 - (30x + 7)
= 30x - 30x + 105 - 7
= 98 square feet
Answer:
D
Step-by-step explanation:
Assuming that the expression is referring to sin²(2πft) and not sin²(2)πft, we can solve as follows:
One trigonometric identity states that sin²x+cos²x = 1. We want to express this in terms of cos²x, so we need to solve for sin²x. Subtracting cos²x from both sides, we get 1-cos²x = sin²x. Plugging (2πft) for x, we get
1-cos²(2πft) = sin²(2πft)
We can plug that into our equation to get
P = I₀²R(1-cos²(2πft)), or D