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irinina [24]
3 years ago
11

How do you write expression 5/6 using a fraction

Mathematics
1 answer:
Luden [163]3 years ago
6 0

Answer:

5/6

Step-by-step explanation:

it is already written as a fraction.

do you mean as a decimal???

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The circumference of a tennis ball is 21<br>cm. How many inches is the circumference?​
Arturiano [62]

Answer:

8.26772

Step-by-step explanation:

1 centimeter is equaled to 0.393701 in inches so multiply it by 21

3 0
3 years ago
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BESTIES PLEASE HELP ASAP WILL GIVE POINTS AND BRAINLIEST. Express as a trinomial (2x-6) (x-4)
zaharov [31]

Answer:

2x² - 14x + 24

Step-by-step explanation:

Use the FOIL method (First, Outside, Inside, Last).

First, multiply the first term of both parenthesis:

2x * x = 2x²

Next, multiply the outside terms of both parenthesis:

2x * -4 = -8x

Then, multiply the inside terms of both parenthesis:

-6 * x = -6x

Finally, multiply the last terms of both parenthesis:

-6 * -4 = 24

Combine like terms:

2x² - 8x - 6x + 24

2x² (-8x - 6x) + 24

2x² (-14x) + 24

2x² - 14x + 24 is your answer.

~

4 0
3 years ago
Read 2 more answers
A plant 3 in. tall grows an average of 0.5 in. each month. Which equation models the flowers height h after x months?
Luden [163]

Answer:the answer is b

Step-by-step explanation:

i cant really explain how i know its kind of second natural to me now

7 0
2 years ago
Question 8
sasho [114]

we are given

system of equations

First equation is

3x-2y=31

Second equation is

3x+2y=-1

now, we can find augmented matrix

A=\begin{pmatrix}3&-2&31\\ 3&2&-1\end{pmatrix}

now, we can change it into reduced row echelon form

step-1: multiply the 1st row by 1/3

A=\begin{pmatrix}1&-2/3&31/3\\ 3&2&-1\end{pmatrix}

step-2:add -3 times the 1st row to the 2nd row

A=\begin{pmatrix}1&-2/3&31/3\\ 0&4&-32\end{pmatrix}

step-3:multiply the 2nd row by 1/4

A=\begin{pmatrix}1&-2/3&31/3\\ 0&1&-8\end{pmatrix}

step-4: add 2/3 times the 2nd row to the 1st row

A=\begin{pmatrix}1&0&5\\ 0&1&-8\end{pmatrix}

so, we get

x=5,y=-8

Answer is (5,-8)

6 0
3 years ago
Read 2 more answers
Solve for x: 5/x^2-4+2/x=2/x-2
IRINA_888 [86]

\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)


5x + 2(x + 2)(x - 2) = 2x(x + 2)


5x + 2(x^2 - 4) = 2x^2 + 4x


5x + 2x^2 - 8 = 2x^2 + 4x


5x - 8 = 4x


x - 8 = 0


x = 8


Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.


Answer: x = 8

6 0
3 years ago
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