3 years ago

Please help me with the questions

Mathematics

1 answer:

Tcecarenko [31]3 years ago

5 0

Step-by-step explanation:

Since, diagonal of a parallelogram bisects it in two triangles of same area.

Hence, area of parallelogram ABCD will be twice the area of triangle ABD.

$area \: of \: { \parallel}^{gm} \: ABCD \\ = 2 \times A(\triangle ABD) \\ = 2 \times 40 \\ = 80 \: {m}^{2}$

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