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nignag [31]
3 years ago
11

Im lonely ): ): ): ): ):

Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

:((((((((((

Step-by-step explanation:

storchak [24]3 years ago
5 0

Answer:

talk to someone

Step-by-step explanation:

okayyyyyyyyy

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Convert 68F to degrees cleius. Using the formula c=5(F-32)/9 where C=temperature in Celsius
Pavel [41]

Answer:

20

Step-by-step explanation:

c = 5(68-32)/9

c = 5(36)/9

c = 20

3 0
3 years ago
Write an equation of the line that passes through (-2, 8) and (-4, -4)
Nady [450]

Answer:

y=6x+20

Step-by-step explanation:


6 0
4 years ago
Find the solution set for this equation.
LuckyWell [14K]

Answer:

m = -5, 0

Step-by-step explanation:

Easiest and quickest way to do this is to graph the equation and find where it intersects the x-axis. If not, then use completing the square or quadratic formula to find your roots.

6 0
3 years ago
What is the measure in degrees of the third angle ?
Illusion [34]

Answer:

C

Step-by-step explanation:

sum of angles in tri are 180

180-35-36=109

7 0
3 years ago
Read 2 more answers
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
3 years ago
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