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masha68 [24]
4 years ago
13

A=9y+3yx Solve for y

Mathematics
2 answers:
algol134 years ago
7 0
A = y(9 + 3x) factor y out of 9y+3yx, then devided both sides by (9+3x)
A/(9+3x) = y

andre [41]4 years ago
3 0

Answer:

y=\frac{A}{(9+3x)}

Step-by-step explanation:

we have

A=9y+3yx

Solve for y

That means -----> isolate the variable y

Step 1

Factor the variable y in the right side

A=y(9+3x)

Step 2

Divide by (9+3x) both sides

A/(9+3x)=y(9+3x)/(9+3x)

Step 3

Simplify

y=\frac{A}{(9+3x)}

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ab + a + 4b+4 = a(b+1) + 4(b+1) = (b +1)(a + 4)



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3 years ago
How can we describe the relationships that exist between circles and lines?
Lunna [17]

circles are 360⁰ and lines are 180⁰

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2 years ago
The sum of the roots of 3x 2 + 11x - 4 = 0 is<br><br> -11/3<br> -4/3<br> 11/3<br> 4/3
givi [52]

Answer:

The correct option is 1.

Step-by-step explanation:

If a quadratic equation is defined as

ax^2+bx+c=0             .... (1)

Then the sum of the roots is -b/a and the product of roots is c/a.

The given equation is

3x^2+11x-4=0          ... (2)

From (1) and (2) we get a=3, b=11 and c=-4.

The sum of roots is

\frac{-b}{a}=-\frac{11}{3}

The sum of roots is -\frac{11}{3}.

Therefore the correct option is 1.

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A particular battery claims to have a mean life of 400 hours with a standard deviation of 30 hours. Approximately what percent o
Svetach [21]

Using the normal distribution, it is found that 25.14% of the batteries will last more than 420 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, we have that the mean and the standard deviation are given, respectively, by:

\mu = 400, \sigma = 30.

The proportion of the batteries will last more than 420 hours is <u>one subtracted by the p-value of Z when X = 420</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{420 - 400}{30}

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

1 - 0.7486 = 0.2514.

0.2514 = 25.14% of the batteries will last more than 420 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

3 0
2 years ago
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