Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is
we have
substitute
Solve for x
subtract 30 both sides
Divide by 11 both sides
The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10
9514 1404 393
Answer:
Step-by-step explanation:
The blanks you're to fill in explain the steps.
The y-intercept is the value of the function when x=0. It is where the graph crosses the y-axis.
f(0) = a·b^0 = a·1 = a
Reading the y-intercept from the graph, we see ...
The y-intercept is 3. The a-value of the function is 3.
__
The point when x=1 is ...
f(1) = a·b^1 = 3b
Reading the value from the graph, we find the point to be (1, 6). This means ...
3b = 6
b = 2 . . . . . . . divide both sides by 3
The point when x=1 is (1, 6). The b-value of the function is 2.
The equation of the function is f(x) = 3·2^x.
I believe it’s 1/2 because 3/6 chances it’ll be a red marble. And 3/6 is also 1/2
<span>half-life means you divide by 2
21.6 / 3.6 = 6 hf (hf = half-life)
then you divide by 2^6
6.02 x 10^23 / 2^6 = 9.40625 x 10^21 atoms
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26
3hf ===> 2^3
10.0 / 2^3 = 1.25 gram (remaining)
answer : 10 - 1.25 = 8.75g
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27
128 / 2^n = 2
64 = 2^n
n = 6
24 /6 = 4
4 days is the half-live of the sample
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28
2.5/4.46 of 50% initial mass
(2.5/4.46) x 0.5 x 2 = 0.5605 g
answer: 2 - 0.5605 = 1.4395 g
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29
2^7 = 128
so 7 half-lifes
7* 8040 = 56200 days
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30
the time of 10 half-lifes
= 10 x 0.334s = 3.34s </span><span>
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