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vagabundo [1.1K]
3 years ago
8

You have two summer jobs. At the Burger Palace you earn $8 per hour. At the community center you teach soccer clinics for $10 pe

r hour. You want to earn at least $200 a week. If x is the number of hours you work at Burger Palace and y is the number of hours you work at the community center, which graph shows all the ways you can earn at least $200 a week? A. 2003-09-04-00-00_files/i0160000.jpg B. 2003-09-04-00-00_files/i0160001.jpg C. 2003-09-04-00-00_files/i0160002.jpg D. 2003-09-04-00-00_files/i0160003.jpg Please select the best answer from the choices provided A B C D Mark this and return

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0
The complete question in the attached figure
 we have that
x-------------> number of hours works at Burger Palace -----> <span>$8
</span>y-------------> number of hours works at <span>community center</span> -----> $10
<span>
8x+10y>=200

using a graph tool
see the attached figure

the answer is the option B
</span><span>
</span>

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a certain pharmaceutical company know that, on average 4% of a certain type of pill has an ingredient that is below the minimum
FinnZ [79.3K]

Using the binomial distribution, it is found that there is a 0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

For each pill, there are only two possible outcomes, either it is acceptable, or it is not. The probability of a pill being acceptable is independent of any other pill, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The sample has 20 pills, hence n = 20.
  • 100 - 4 = 96% are acceptable, hence p = 0.96

The probability that <u>fewer that 5 in a sample of 20 pills</u> will be acceptable is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.96)^{0}.(0.04)^{20} = 0

P(X = 1) = C_{20,1}.(0.96)^{1}.(0.04)^{19} = 0

P(X = 2) = C_{20,2}.(0.96)^{2}.(0.04)^{18} = 0

P(X = 3) = C_{20,3}.(0.96)^{3}.(0.04)^{17} = 0

P(X = 4) = C_{20,4}.(0.96)^{4}.(0.04)^{16} = 0

0% probability that fewer that 5 in a sample of 20 pills will be acceptable.

A similar problem is given at brainly.com/question/24863377

8 0
2 years ago
A craft stores sells ribbons in packages of different lengths the price of each package is shown which package offers the lowest
ankoles [38]

Answer:

Package 3 has the lowest unit price.

Step-by-step explanation:

7 0
3 years ago
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A small business ships specialty homemade candies to anywhere in the world. Past records indicate that the weight of orders is n
Fantom [35]

Answer:

90% confidence interval for the true mean weight of orders is between a lower limit of 103.8645 grams and an upper limit of 116.1355 grams.

Step-by-step explanation:

Confidence interval for true mean weight is given as sample mean +/- margin of error (E)

sample mean = 110 g

sample sd = 14 g

n = 16

degree of freedom = n - 1 = 16 - 1 = 15

confidence level = 90% = 0.9

significance level = 1 - C = 1 - 0.9 = 0.1 = 10%

critical value (t) corresponding to 15 degrees of freedom and 10% significance level is 1.753

E = t × sample sd/√n = 1.753×14/√16 = 6.1355 g

Lower limit of sample mean = sample mean - E = 110 - 6.1355 = 103.8645 g

Upper limit of sample mean = sample mean + E = 110 + 6.1355 = 116.1355 g

90% confidence interval is (103.8645, 116.1355)

4 0
3 years ago
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a fruit company delivers its fruit in two types of boxes: large and small. A delivery of 3 large boxes and 2 small boxes has a t
TiliK225 [7]

Answer:

x = the wight of the large box

y = the weight of the small box

A delivery of 3 large boxes and 2 small boxes has a total weight of 73 kilograms.

3x + 2y = 73

A delivery of 8 large boxes and 4 small boxes has a total weight of 177 kilograms.

8x + 4y = 177

by solving the system of equations

3x + 2y = 73

8x + 4y = 177

we find

x = 15.5 kg

y = 13.25 kg

the large box weights 15.5 kg.

the small box weights 13.25 kg.

5 0
2 years ago
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If anyone Answer this question with POLITICALLY CORRECT answer I'll give you 25+ Points
Tresset [83]

Answer:

\sqrt[4]{x^5}

Step-by-step explanation:

A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

x^{\frac{3}{4}}x^{\frac{1}{2} } =x^{\frac{3}{4}}x^{\frac{2}{4} } =x^{\frac{3+2}{4}} =x^{\frac{5}{4}}

Now convert to the radical.

x^{\frac{5}{4}} = \sqrt[4]{x^5}

8 0
3 years ago
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