Answer:
936 is the correct option
Answer:
5/12
Step-by-step explanation:
You have to make it a common denomator and then subract until equeal.
Answer:
![m^2 +1](https://tex.z-dn.net/?f=m%5E2%20%2B1)
Explanation:
All the other expressions can be factorized. Let's see why:
1) ![m^3 +1](https://tex.z-dn.net/?f=m%5E3%20%2B1)
This is the sum of the cubes, and this can be factorized as follows:
![a^3+b^3=(a+b)(a^2-ab+b^2)](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%3D%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29)
In this case, a=m and b=1, so we can factorize as
![m^3+1=(m+1)(m^2-m+1)](https://tex.z-dn.net/?f=m%5E3%2B1%3D%28m%2B1%29%28m%5E2-m%2B1%29)
2) ![m^3-1](https://tex.z-dn.net/?f=m%5E3-1)
This is the difference between two cubes, and this can be factorized as follows:
![a^3-b^3=(a-b)(a^2+ab+b^2)](https://tex.z-dn.net/?f=a%5E3-b%5E3%3D%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29)
In this case, a=m and b=1, so we can factorize as
![m^3-1=(m-1)(m^2+m+1)](https://tex.z-dn.net/?f=m%5E3-1%3D%28m-1%29%28m%5E2%2Bm%2B1%29)
3) ![m^2-1](https://tex.z-dn.net/?f=m%5E2-1)
This is the difference between two square numbers, and it can be factorized as follows
![(a^2-b^2)=(a+b)(a-b)](https://tex.z-dn.net/?f=%28a%5E2-b%5E2%29%3D%28a%2Bb%29%28a-b%29)
In this case, a=m and b=1, so we can factorize as
![m^2-1=(m+1)(m-1)](https://tex.z-dn.net/?f=m%5E2-1%3D%28m%2B1%29%28m-1%29)
find the prime factors in each term to find the GCF
answer is 6x^2