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2 years ago

Write down the 3rd term in the sequence given by: T(n) = n2 + n

1 answer:

8 0

The solution for the problem is:
I will first get the first five terms so that I could easily locate the third term of this problem:So, substituting the values:
T(1) = 1^2 = 1T(2) = 2^2 = 4T(3) = 3^2 = 9T(4) = 4^2 = 16T(5) = 5^2 =25
So the third terms is T(3) = 3^2 = 9

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Please tell me the answers!!!

Sophie [7]

Answer:

first one is c second one is c and a

Step-by-step explanation:

8 0

2 years ago

A box contains 19 large marbles and 18 small marbles. Each marble is either green or white. 9 of the large marbles are green, an

pshichka [43]

If a marble is randomly selected from the box, then the probability

that it is small or green is 0.7297

Step-by-step explanation:

A box contains 19 large marbles and 18 small marbles

Each marble is either green or white

9 of the large marbles are green, and 8 of the small marbles are white

If a marble is randomly selected from the box, we need to find the

probability that it is small or green

1. Find P(small) ⇒ P(s)

2.Find P(green) ⇒ P(g)

3. Find P(small and green) ⇒ P(s and g)

4. Use the rule P(small or green) = P(s) + P(g) - P(s and g)

∵ The box contains 19 large marbles and 18 small marbles

∴ The total number of marbles = 19 + 18 = 37

∴ P(s) = $\frac{18}{37}$

∵ There are 8 small white marbles

∵ There are 18 small marbles

∴ The number of small green marbles = 18 - 8 = 10

∴ P(s and g) = $\frac{10}{37}$

∵ There are 9 large green marbles

∵ There are 10 small green marbles

∴ The number of green marbles = 9 + 10 = 19

∴ P(g) = $\frac{19}{37}$

∵ P(small or green) = P(s) + P(g) - P(s and g)

∴ P(small or green) = $\frac{18}{37}+\frac{19}{37}-\frac{10}{37}$

∴ P(small or green) = $\frac{27}{37}$ = 0.7297

If a marble is randomly selected from the box, then the probability

that it is small or green is 0.7297

Learn more:

you can learn more about probability in brainly.com/question/13053309

#Learnwithbrainly

5 0

2 years ago

WILL MARK BRAINLIEST!! Which of the following ordered pairs are y-intercepts? Check all that apply.

Y_Kistochka [10]

Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.

So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.

8 0

3 years ago

Read 2 more answers

Points (−3, 5) and (3, 5) on the coordinate grid below show the positions of two players on a tennis court:

Anna35 [415]

Answer:

4. Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

Step-by-step explanation:

Player 1's position is (-3, 5).

It means that it is 3 units left from the origin and 5 units above the origin.

Player 2's position is (3, 5).

It means that it is 3 units right from the origin and 5 units above the origin.

Hence, the two points are on the same horizontal line bisected by the y-axis.

So, Player 2's position is Player 1's position reflected across the y-axis; only the signs of the x-coordinates of Player 1 and Player 2 are different.

3 0

2 years ago

What’s the equation for the order pairs (1,-5) and (-2,5)

liq [111]

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})\qquad
(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-5)}{-2-1}\implies \cfrac{5+5}{-2-1}\implies \cfrac{10}{-3}$

$\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-(-5)=-\cfrac{10}{3}(x-1)\implies y+5=-\cfrac{10}{3}x+\cfrac{10}{3}
\\\\\\
y=-\cfrac{10}{3}x+\cfrac{10}{3}-5\implies y=-\cfrac{10}{3}x-\cfrac{5}{3}$

6 0

2 years ago