Need Help, thanks:)<br><br> Please help

two business partners, Ellen and Bob, invested money in their business at a ratio of 3 to 7. Bob invested the greater amount. th

Shtirlitz [24]

Answer:

Ellen invested $60 and Bob invested $140

Step-by-step explanation:

let the two amounts invested by 3x and 7x

(notice 3x : 7x = 3 : 7 )

then 3x + 7x = 200

10x = 200

x = 20

then 3x = 3(20) = 60

and 7x = 7(20) = 140

60+140=200

7 0

3 years ago

A slitter assembly contains 48 blades. Five blades are selected at random and evaluated each day of sharpness. If any dull blade

Alex73 [517]

Answer:

Part a

The probability that assembly is replaced the first day is 0.7069.

Part b

The probability that assembly is replaced no replaced until the third day of evaluation is 0.0607.

Part c

The probability that the assembly is not replaced until the third day of evaluation is 0.2811.

Step-by-step explanation:

Hypergeometric Distribution: A random variable x that represents number of success of the n trails without replacement and M represents number of success of the N trails without replacement is termed as the hypergeometric distribution. Moreover, it consists of fixed number of trails and also the two possible outcomes for each trail.

It occurs when there is finite population and samples are taken without replacement.

The probability distribution of the hyper geometric is,

$P(x,N,n,M)=\frac{(\limits^M_x)(\imits^{N-M}_{n-x})}{(\limits^N_n)}$

Here x is the success in the sample of n trails, N represents the total population, n represents the random sample from the total population and M represents the success in the population.

Probability that at least one of the trail is succeed is,

$P(x\geq1)=1-P(x$

(a)

Compute the probability that the assembly is replaced the first day.

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48.

Number of blades selected at random from the assembly n= 5

Number of blades in an assembly dull is M = 10.

The probability mass function is,

$P(X=x)=\frac{[\limits^M_x][\limits^{N-M}_{n-x}]}{[\limits^N_n]};x=0,1,2,...,n\\\\=\frac{[\limits^{10}_x][\limits^{48-10}_{5-x}]}{[\limits^{48}_5]}$

The probability that assembly is replaced the first day means the probability that at least one blade is dull is,

$P(x\geq 1)=1- P(x$

(b)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48

Number of blades selected at random from the assembly N = 5

Number of blades in an assembly dull is M = 10

From the information,

The probability that assembly is replaced (P) is 0.7069.

The probability that assembly is not replaced is (Q) is,

$q=1-p\\= 1-0.7069= 0.2931$

The geometric probability mass function is,

$P(X = x)= q^{x-1} p; x =1,2,....=(0.2931)^{x-1}(0.7069)$

The probability that assembly is replaced no replaced until the third day of evaluation is,

$P(X = 3)=(0.2931)^{3-1}(0.7069)\\=(0.2931)^2(0.7069)= 0.0607$

(c)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48

Number of blades selected at random from the assembly n = 5

Suppose that on the first day of the evaluation two of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M = 2.

$P(x=0)=\frac{(\limits^2_0)(\limits^{48-2}_{5-0})}{\limits^{48}_5}\\\\=\frac{(\limits^{46}_5)}{(\limits^{48}_5)}\\\\= 0.8005$

Suppose that on the second day of the evaluation six of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M = 6.

$P(x=0)=\frac{(\limits^6_0)(\limits^{48-6}_{5-0})}{(\limits^{48}_5)}\\\\=\frac{(\limits^{42}_5}{(\limits^{48}_5)}\\\\= 0.4968$

Suppose that on the third day of the evaluation ten of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M

= 10.

$P(x\geq 1)=1- P(x$

The probability that the assembly is not replaced until the third day of evaluation is,

P(The assembly is not replaced until the third day)=P(The assembly is not replaced first day) x P(The assembly is not replaced second day) x P(The assembly is replaced third day)

=(0.8005)(0.4968)(0.7069)= 0.2811

5 0

3 years ago

6. Suppose you decide to make and sell silk flower arrangements. You spend $220.00 on materials. You sell each flower arrangemen

Gekata [30.6K]

The profit would you make if sold 23 silk flower arrangements be $21.5.

<h3>What is Unitary method?</h3>

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

spend on materials = 220

Price for each flower =10.50

If 23 flowers are sold price would be,

= 10.50*23

=241.5

Hence, the profit would be = 241.5-220

= $21.5

Learn more about unitary method here:

brainly.com/question/22056199

#SPJ1

7 0

2 years ago

To find the percent of the yellow tint in the new mixture?

Ivanshal [37]

1)We need to know the amount of yellow tint in the old mixture.

amount of yellow tint=30% of 40 liters
30%=30/100=0.3

Amount of yellow tint=0.3(40 liters)=12 liters.

2)We need to find the amount of yellow tint in the new mixture.

amount of yellow tint in the new mixture=12 liters + 9 liters=21 liters.

3) we calculate the amount of the new mixture:
amount of new mixture=40 liters + 9 liters=49 liters

4) we compute the percent of yellow tint in the new mixture:

percent of yellow tint =(amount of yellow tint / amount of mixture)*100

percent of yellow tint=(21 liters / 49 liters)100≈42.9%

Answer: The percent of yellow tint in the new mixture is 42.9%.

note: if this answer is not correct you can try it with 42.8%

6 0

3 years ago

Which sequence of transformations on the red triangle will map it onto the missing portion of the square?

anyanavicka [17]

Answer:

A 90° counterclockwise rotation about the origin and then a translation 16 units right and 16 units up

Solution -Rotating the triangle 90° counterclockwise will take the triangle to 3rd quadrant and then further moving it 16 steps right will take it to 4th quadrant and followed by 16 steps upward will take it to the desired position which is in 1st quadrant.

7 0

3 years ago

Need Help, thanks:) Please help