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dem82 [27]
4 years ago
6

Find (f*f)(3) f(x)=x^2-x

Mathematics
1 answer:
mote1985 [20]4 years ago
7 0
Fof(x) = f(x^2 - x) = (x^2 - x)^2 - (x^2 - x)
f(3) = (9 - 3)^2  - (9 - 3)
f(3) = 6^2 - 6
f(3) = 36 - 6 = 30

I wouldn't want to bet the farm on this. If you get another answer that is reasonable, take it.
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If a pyramid had a base of area 4 and height of 6, what is the volume
lilavasa [31]
24 because 4x6 is 24
4 0
3 years ago
Read 2 more answers
Find the product and enter it in the box below. Enter your answer as a
Helen [10]
Idk I just want points
8 0
4 years ago
Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number
Masja [62]

Answer:

<h2>√512 by √512 </h2>

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

Perimeter P = 2(Length + Breadth)

A = xy and P = 2(x+y)

If the area of the rectangle is 512m², then 512 = xy

x = 512/y

Substituting x = 512/y into the formula for calculating the perimeter;

P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

-1024y⁻² = -2

512y⁻² = 1

y⁻² = 1/512

1/y² = 1/512

y²  = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

Hence, the dimensions of a rectangle is √512 m  by √512 m

5 0
4 years ago
Which expressions are equivalent to 616? Check all that apply.<br> (60) 10<br> (62)<br> (61) 16
levacccp [35]

Answer:

(6^-4)^-4, (6^-2)^-8, (6^8)^2

5 0
3 years ago
What is the ultimate goal when solving equations? What do you want your final answer to look like?
STALIN [3.7K]

Answer:

\huge\boxed{\text{To get x on one side of the equation:} \ \ x = ...}

Step-by-step explanation:

When we solve for an equation, our goal is to find the value of the variable. Any variable can be used, but for the time being let’s assume we use x.

We can algebraeically solve equations until we get the value of x - in which we will have x equal to something.

Say we have the equation 5x+5=20. Our goal is to find the value of x. <u>We can do this by getting x isolated on one side so we have something equal to x</u>.

We can subtract 5 from both sides and divide both sides by 5.

5x=15\\\\x=3

We now know the value of x since it’s on one side of the equation.

Hope this helped!

5 0
3 years ago
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