Find the line with the slope m=½ through point (8,1)
1 answer:
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Answer:
0.0048cm/s
Step-by-step explanation:
Volume of the spherical balloon is expressed as;
dV/dt = dV/dr * dr/dt
Given
dV/dt = 5cm³/s
dV/dr = 4πr²
Since V = 972picm³
972π = 4/3πr³
972 = 4/3r³
4r³ = 972 * 3
r³ = (972 *3)/4
r³ = 729
r = ∛729
r = 9cm
dV/dr = 4π(9)²
dV/dr = 324π
dV/dt = dV/dr * dr/dt
5 = 324πdr/dt
dr/dt = 5/324π
dr/dt = 5/324(3.14)
dr/dt = 5/1017.36
dr/dt = 0.0048cm/s
Answer:
volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( x + b )² dx
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)
from the image;
the equation of AB will be;
y-b / b-0 = x-0 / 0-a
(y-b)(0-a) = (b-0)(x-0)
0 - ay -0 + ba = bx - 0 - 0 + 0
-ay + ba = bx
ay = -bx + ba
divide through by a
y = x + ba/a
y = x + b
so R is bounded by y = x + b and y =0, 0 ≤ x ≤ a
The volume of the solid revolving R about x axis is;
dv = Area × thickness
= π( Radius)² dx
= π ( x + b )² dx
V = π ₀∫^a ( x + b )² dx
Therefore, volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( x + b )² dx