Answer:
Approx 61.554 feet
Step-by-step explanation:
Since we are dealing with the opposite and adjacent sides, we will use tangent as our ratio.
Since the angle of elevation is 72 degrees, the left side of our equation is 
.
The right side of the equation is opposite over adjacent.
Set these equal to each other.
Simplify.
x is approximately 61.554.
Answer:
f(x) = 3x + 2
Step-by-step explanation:
That's easy to find out. You have your input number, which is your x value, and you have your output number which is your y value (or f(x)).
All you have to do is see if each of the proposed answer works for ALL entries in the data set.
f(x) = 3x + 2
for x = 3 ===> 11 = 3 (3) + 2 = 11 YES
for x = 5 ===> 17 = 3 (5) + 2 = 17 YES
for x = 7 ===> 23 = 3 (7) + 2 = 23 YES
for x = 9 ===> 29 = 3 (9) + 2 = 29 YES
f(x) = 2x + 5
for x = 3 ===> 11 = 2 (3) + 5 = 11 YES
for x = 5 ===> 17 = 2 (5) + 5 = 15 NO - we stop here for this function
f(x) = x + 7
for x = 3 ===> 11 = (3) + 7 = 10 NO - we stop here for this function
f(x) = 3x + 1
for x = 3 ===> 11 = 3 (3) + 1 = 10 NO - we stop here for this function
Answer:
Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself
Step-by-step explanation:
Okay so you have a weigh of 8 and a diagonal of 13.
If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.
Pythagorean theroum: a^2+b^2=c^2
Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.
In this case I’m substituting a for 8.
8^2+b^2=13^2
Solve the squares
64+b^2= 169
Isolate the b
b^2=105
Now square root 105
√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.
-- 'Truncated' to one decimal place, it's 9.9 ,
-- 'Rounded' to one decimal place, it's 9.9 .
(These two operations don't always produce the same result.)
What exactly was the purpose of posting this?
