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Lena [83]
2 years ago
11

What is the answer to the problem? 30 = -5(m + 6) + m

Mathematics
1 answer:
-BARSIC- [3]2 years ago
8 0

30=−5(m+6)+m

Step 1: Simplify both sides of the equation.

30=−5(m+6)+m

30=(−5)(m)+(−5)(6)+m(Distribute)

30=−5m+−30+m

30=(−5m+m)+(−30)(Combine Like Terms)

30=−4m+−30

30=−4m−30

Step 2: Flip the equation.

−4m−30=30

Step 3: Add 30 to both sides.

−4m−30+30=30+30

−4m=60

Step 4: Divide both sides by -4.

−4m

−4

=

60

−4

m=−15

Answer:

m=−15

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Write the inverse function, <br> f^-1 (x), for the function <br> f (x) = 2x + 3
cricket20 [7]

f(x) = 2x + 3

y = 2x + 3

Subtract the sides of the equation minus 3

y - 3 = 2x

Divided the sides of the equation by 2

\frac{y - 3}{2} = x \\

So ;

{f}^{ - 1}(x) =  \frac{x - 3}{2} \\

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6 0
3 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

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1 year ago
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amid [387]
8:2 hope this helps
7 0
3 years ago
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Brenda collected this data from an experiment.
Gelneren [198K]

Answer:

7.04

Step-by-step explanation:

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The substitution equation is h = 0.6t + 0.44

Substituting 11, we have

h = 0.6(11) + 0.44

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8 0
3 years ago
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