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3 years ago

What is the pythetherom

Mathematics

1 answer:

pashok25 [27]3 years ago

8 0

Answer:

The Pythagorean Theorem states: In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).

The Pythagorean theorem can be written as an equation relating the lengths of the sides a, b and c, often called the Pythagorean equation:

a2 + b2 = c2

Step-by-step explanation:

You might be interested in

Can someone please help me I’m stuck

olga_2 [115]

Answer:

Step-by-step explanation:

You have to do base x height divided by 2

50/2

8 0

3 years ago

A figure has been dilated from the origin by a scale factor of

Darya [45]

Answer:

See Explanation

Step-by-step explanation:

The question has missing details. So, I'll solve using a general assumption.

Let one of the coordinates of the figure be

$A = (x,y)$

Let the scale factor be n

When dilated, the new figure is:

$A' = n * A$

$A' = n * (x,y)$

To return the image back to the original figure, the new scale factor mus be a reciprocal of the previous scale factor i.e. $\frac{1}{n}$

So:

$A = A' * \frac{1}{n}$

Substitute n(x,y) for A';

$A = n(x,y) * \frac{1}{n}$

$A = \frac{n(x,y)}{n}$

$A = (x,y)$

Take for instance:

$A = (2,3)$

$n = 2$ -- scale factor

$A' = n * A$

$A' = 2 * (2,3)$

$A' = (4,6)$

To get A from A', using the analysis above

$A = \frac{1}{2} * (4,6)$

$A = (2,3)$

6 0

3 years ago

A heron is perched in a tree 50 feet above sea level. Directly below the heron, a pelican is flying 17 feet above sea level. Dir

Olegator [25]

Answer:

A. The difference in height between the pelican and the heron is -33 feet.

E. The difference in height between the pelican and the trout is 40 feet.

F. The distance between the heights of the pelican and the trout is 40 feet.

Step-by-step explanation:

<h3> The missing statements are:</h3><h3> A. The difference in height between the pelican and the heron is -33 feet</h3><h3> B. The difference in height between the pelican and the heron is 33 feet</h3><h3> C. The distance between the heights of the pelican and heron is -33 feet</h3><h3> D. The difference in height between the pelican and the trout is -40 feet</h3><h3> E. The difference in height between the pelican and the trout is 40 feet</h3><h3> F. The distance between the heights of the pelican and the trout is 40 feet.</h3><h3 />

Let be 0 the sea level.

Since the heron is perched in a tree 50 feet above sea level and directly below the heron the pelican is flying 17 feet above sea level, you can find the difference in height between the pelican and the heron by subtracting 50 feet from 17 feet.

Then, you get that this is:

$17\ feet-50\ feet=-33\ feet$

Now, according the the information given in the exercise, you know that the trough is swimming directly below them and its height is 23 feet below sea level. If you represent this with an integer, this is:

$-23$

Therefore you can find the difference in height between the pelican and the trout through the following subtraction:

$17\ feet-(-23\ feet)=17\ feet+23\ feet=40\ feet$

And the distance between them is 40 feet too.

8 0

3 years ago

Evaluate the expression using the values in the left column to complete the table

egoroff_w [7]

Answer/Step-by-step explanation:

A. $4b + 3b$

Using b = 2

$4(2) + 3(2) = 8 + 6 = 14$

Using b = 4

$4(4) + 3(4) = 16 + 12 = 28$

Using b = 6

$4(6) + 3(6) = 24 + 18 = 42$

Using b = 8

$4(8) + 3(8) = 32 + 24 = 56$

Using b = 10

$4(10) + 3(10) = 40 + 30 = 70$

Using b = 2

$4(12) + 3(12) = 48 + 36 = 84$

B. $3(x - 2)$

Using x = 3

$3(3 - 2) = 3(1) = 3$

Using x = 5

$3(5 - 2) = 3(3) = 9$

Using x = 7

$3(7 - 2) = 3(5) = 15$

Using x = 9

$3(9 - 2) = 3(7) = 21$

Using x = 11

$3(11 - 2) = 3(9) = 27$

Using x = 13

$3(13 - 2) = 3(11) = 33$

C. $5(4a - 1)$

Using a = 2

$5(4(2) - 1) = 5(8 - 1) = 5(7) = 35$

Using a = 3

$5(4(3) - 1) = 5(12 - 1) = 5(11) = 55$

Using a = 4

$5(4(4) - 1) = 5(16 - 1) = 5(15) = 75$

Using a = 5

$5(4(5) - 1) = 5(20 - 1) = 5(19) = 95$

Using a = 6

$5(4(6) - 1) = 5(24 - 1) = 5(23) = 115$

Using a = 7

$5(4(7) - 1) = 5(28 - 1) = 5(27) = 135$

D. $6y - 2y + 4$

Using y = 2

$6(2) - 2(2) + 4 = 12 - 4 + 4 = 12$

Using y = 3

$6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16$

Using y = 5

$6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24$

Using y = 10

$6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44$

Using y = 8

$6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36$

Using y = 6

$6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28$

7 0

3 years ago

You invested $500 in a savings account and after three years you had $650 in your bank. What was the interest rate? Use the equa

SpyIntel [72]

Answer:

An increase of 43.3% per year

Step-by-step explanation:

using the equation, plug in the respective variables. 650 =500R3, 3 times 500 is 1500. 650=1,500R. divide both sides by 1500 to get .4333, 3 repeating. .433 in percent form is 43.3%. (I just use 650 out of 500 or 650/500 which is 1.3 divided by 3 because 3 years to get the same amount)

6 0

3 years ago