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faust18 [17]
2 years ago
11

Laura's Burgers cooks its burgers either well done or medium. Last night, the restaurant served 57 well-done burgers and 3 mediu

m burgers. What percentage of the burgers served were well done?
Mathematics
1 answer:
SSSSS [86.1K]2 years ago
3 0

Answer:

About 95% of the burgers were well done. 57/60 = 95%

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Solve −2(−4n + 1)+5(25n − 8)=−62. <br><br><br><br> n= ?
In-s [12.5K]
N= -20/133

Step 1: Simplify both sides of the equation.
−
2
(
−
4
n
+
1
)
+
5
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25
n
−
8
)
=
−
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(
−
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−
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n
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+
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1
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5
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+
(
5
)
(
−
8
)
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−
62
(Distribute)
8
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2
+
125
n
+
−
40
=
−
62
(
8
n
+
125
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−
2
+
−
40
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(Combine Like Terms)
133
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−
42
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133
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−
62
Step 2: Add 42 to both sides.
133
n
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42
+
42
=
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62
+
42
133
n
=
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20
Step 3: Divide both sides by 133.
133
n
133
=
−
20
133
n
=
−
20
133
5 0
2 years ago
Read 2 more answers
NEED HELP FAST I WILL MARK BRAINLYEST
Phoenix [80]

Answer:

13/48

Step-by-step explanation:

13/6 / 8 = 13/6 x 1/8

13 x 1 = 13

6 x 8 = 48

13/48

7 0
2 years ago
Read 2 more answers
The volume of a box is given by V = 2x3-11x2 +10x +8. One side is (x - 4) and another side is (2x + 1).
user100 [1]

Answer:

The length of the third side is ( x - 2 )

Step-by-step explanation:

Volume of a box is the product of its length, width and height.

Volume of box = length × width × height.

One side is (x - 4) and another side is (2x + 1).

These given sides can be either length, height or width.

The volume of a box is given by V = 2x3-11x2 +10x +8. This means each of the sides are factors of the volume. To get the third side, we divide the volume by the product of the two given sides.

Product of the two given sides =

( x-4 ) (2x + 1) = 2x^2 + x - 8x + 4

= 2x^2 - 7x - 4

The long division is shown on the attached photo

The length of the third side is ( x - 2 )

4 0
3 years ago
Read 2 more answers
Aubrey wants to buy a pair of jeans of $29.99 and a shirt for $15.75. How much money does Aubrey need to buy both items?
aniked [119]

Answer:

$55-$60

Step-by-step explanation:

3 0
2 years ago
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What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
3 years ago
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