Question

Circle O and circle P are congruent. Given that AB = DE , what can you conclude from the diagram?

Answer 1

Since the radius is the same, that means that OBA=PDE

Answer 2

Answer: We can conclude that, $\triangle OAB\cong \triangle PD E$.

Explanation: Since, If two circles are congruent then their radius is equal.

Therefore, we can say,  OA=OB=PD=PE.

Since, in triangles OAB and  PDE,

OA=PD,

OB=PE,

And, AB=DE ( given)

Therefore, by SSS postulate we can say,  $\triangle OAB\cong \triangle PD E$ .

Note: we can also say by the diagram, $\angle AOB$ and $\angle PD E$ are congruent.