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zepelin [54]
4 years ago
11

Please answer this question i really need your help

Mathematics
1 answer:
navik [9.2K]4 years ago
8 0
Functions:graph B,mapping A, Table B
Grape B is a function because it passes the vertical line test ( meaning when I draw a vertical line any where on the graph the line only touched one point),mapping A is a function because each x value has only one y value same with table.
Non function: graph A, mapping B, Table A
Graph A does not pass vertical line test so it is not a function, mapping B and Table A both have an x value that has two y values and that is not a function.
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Which expressions are equivalent? Select two answers.
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<h2>A, C</h2>

Step-by-step explanation:

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A.\\\\\dfrac{1}{5}(x-50)=\dfrac{1}{5}x-\left(\dfrac{1}{5}\right)(50)=\dfrac{1}{5}x-\dfrac{50}{5}=\dfrac{1}{5}x-10\\\\B.\\\\-\dfrac{1}{3}(3x+18)=\left(-\dfrac{1}{3}\right)(3x)+\left(-\dfrac{1}{3}\right)(18)=-\dfrac{3}{3}x-\dfrac{18}{3}=-x-6\\\\-x-6\neq\dfrac{1}{3}x-6

C.\\\\\dfrac{1}{2}(x+16)=\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)(16)=\dfrac{1}{2}x+\dfrac{16}{2}=\dfrac{1}{2}x+8\\\\D.\\\\\dfrac{1}{8}(8x+8)=\left(\dfrac{1}{8}\right)(8x)+\left(\dfrac{1}{8}\right)(8)=\dfrac{8}{8}x+\dfrac{8}{8}=x+1\\\\x+1\neq\dfrac{1}{8}x+1\\\\E.\\\\-\dfrac{1}{4}(x+2)=-\dfrac{1}{4}x+\left(\dfrac{1}{4}\right)(2)=-\dfrac{1}{4}x+\dfrac{2\!\!\!\!\diagup^1}{4\!\!\!\!\!\diagup_2}=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\-\dfrac{1}{4}x+\dfrac{1}{2}\neq-\dfrac{1}{4}x+2

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Step-by-step explanation:

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