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ahrayia [7]
3 years ago
5

3.7 as a fraction simplified​

Mathematics
1 answer:
malfutka [58]3 years ago
8 0

Answer:3 7/10

Step-by-step explanation:

:)

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Part A: If (7exponent2)exponentX = 1, what is the value of X? Explain your answer.
yKpoI14uk [10]
Answers:
Part A: The value of x must be 0
Part B: The value of x can be any real number

----------------------------------------------------------------

Explanation:

Part A) We have the equation (7^2)^x = 1 which simplifies to 7^(2x) = 1. The only way to get the left side equal to the right side is to have the exponent of 2x equal zero. If 2x = 0, then x = 0. So that's why x = 0 is the only solution here.

--------------

Part B) Similar to part A above, but the exponent is slightly different now. We have (7^0)^x = 1 which turns into 7^(0*x) = 1. The exponent 0*x is really 0 no matter what x is. We can plug in any real number we want for x and the left side will always be 1. This is why the solution set to this equation is the set of all real numbers. 
3 0
3 years ago
Complete the second equation below so that the terms in the system align.
cricket20 [7]

The equation is 3x+2y= -22

3 0
3 years ago
Read 2 more answers
The number 99 is increased to 104. What is the percentage by which the number was increased, to the nearest tenth of a percent?
Tanya [424]

Answer:

5.1

Step-by-step explanation:

I think im not shure

3 0
3 years ago
Read 2 more answers
A) The equilibrium prices P1 and P2 for two goods satisfy the equations:
Allisa [31]

The value of P1 and P2 using the inverse matrix is 5 and 6 respectively.

<h3 />

The equilibrium prices of the three independent commodities using the inverse matrix are P1 = 4, P2 = 7, P3 = 8 respectively.

<h3>What is a matrix?</h3>

A matrix can be defined as a collection of integers(numbers that are either positive or negative) that are organized in rows and columns to construct a rectangular array. The numbers in this matrix system are referred to as elements.

To determine the values of P1 and P2 for the system of equations given by using an inverse matrix, we have:

a)

9P1 + P2 = 51

3P1 +4P2 = 39

Representing the above data in matrix form, we have:

\left[\begin{array}{cc}9&1\\3&4\\ \end{array}\right] \left[\begin{array}{c} \mathbf{P_1} \\ \mathbf{P_2}\\ \end{array}\right] =  \left[\begin{array}{c} \mathbf{51} \\ \mathbf{39} \\ \end{array}\right] which is in the form AX = B

  • In order for us to determine the values of P1 and P2, Let take the inverse of A⁻¹ on both sides of the AX= B, we have:

\mathbf{{A^{-1} AX} = A^{-1} B}

X = A⁻¹ B

Let's start by finding A⁻¹;

\mathbf{A = \left[\begin{array}{cc}9&1\\3&4\end{array}\right] }

\mathbf{A^{-1} = \dfrac{1}{36-3}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] }

\mathbf{A^{-1} = \dfrac{1}{33}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] }

Now, Let's Find A⁻¹B;

\mathbf{A^{-1}B = \dfrac{1}{33}\left[\begin{array}{cc}4&-1\\3&9\end{array}\right] \left[\begin{array}{c}51\\39\\ \end{array}\right] }

\mathbf{\implies \dfrac{1}{33}\left[\begin{array}{cc}204&-39\\-153&+351\end{array}\right]  }

\mathbf{\implies \left[\begin{array}{c}\dfrac{165}{33}\\ \\ \dfrac{198}{33}\end{array}\right]  }

\mathbf{\implies \left[\begin{array}{c}5\\ \\ 6\end{array}\right]  }

\left[\begin{array}{c}\mathbf{P_1}\\  \mathbf{P_2}\end{array}\right]= \left[\begin{array}{c}5\\ 6 \end{array}\right] }

Therefore, we can conclude that the value of P1 and P2 using the inverse matrix is 5 and 6 respectively.

b)

To determine the equilibrium prices of the three independent commodities using the inverse matrix, we have:

P₁ + 2P₂ + 3P₃ = 42

2P₁ + P₂ + 4P₃ = 47

P₁ + 3P₂ + 4P₃ = 57

The matrix in AX = B form is computed as:

\implies\left[ \begin{array}{ccc}1&2&3\\2&1&4\\1&3&4\end{array}\right] \left[\begin{array}{c}P_1\\P_2\\P_3  \end{array}\right] = \left[\begin{array}{c}42\\47\\ 57\end{array}\right]

\mathbf{A^{-1} = \dfrac{1}{|A|} \  (adj \  A)}

\mathbf{A^{-1} = \dfrac{1}{1(4-12) -2(8-4) +3(6-1)} \left[\begin{array}{ccc}-8&4&5\\1&1&-1\\5&2&-3\end{array}\right] }^1

\mathbf{A^{-1}B = -1 \left[\begin{array}{ccc}-8&1&5\\-4&1&2\\5&2&-3\end{array}\right] }\left[\begin{array}{c}42\\47\\57\end{array}\right]

\mathbf{A^{-1}B = -\left[\begin{array}{ccc}-336&+47&+285\\-168&+47&+114\\210&-47&-171\end{array}\right] }

\mathbf{A^{-1}B = -\left[\begin{array}{c}-4\\-7\\-8\end{array}\right] }

\mathbf{A^{-1}B = \left[\begin{array}{c}4\\7\\8\end{array}\right] }

Therefore, we can conclude that the values of P1 = 4, P2 = 7, P3 = 8 respectively.

Learn more about matrix here:

brainly.com/question/1821869

3 0
2 years ago
What is the probability that the reader’s favorite is Rowling given that the reader is a teen?
Stells [14]

Answer:

Probability = 0.500

Step-by-step explanation:

If it is given that the reader is a teen, we have a total of 80 readers, where 40 of those readers have Rowling as their favorite.

So the probability that the reader's favorite is Rowling given that the reader is a teen is the number of teen readers that have Rowling as favorite (40) over the total number of teen readers (80)

Probability = 40 / 80 = 0.500

8 0
4 years ago
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