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3 years ago

I need 1/8,0.025(5 repeating), 0.2, and -1/7 in order from least to greatest.

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

5 0

That would be -1/7, 0.025(5 repeating), 0.2, 1/8

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How do I solve 3x(4x-15)

inna [77]

3x(4x - 15) < Given
12x^2 - 45x < Distributive law of property

By the way, you are simplifying not solving. You solve equations and simplify expressions.

7 0

3 years ago

(x/16)-(x+2)/8))=2<br><br><br><br> PLS HELP ME BRAINLIEST TO THE FIRST CORRECT ANSWER

ArbitrLikvidat [17]

Simplify both sides of the equation

x/16−(x+2/8) = 2x/16 + −1/8x + −1/4 = 2

Distribute

1/16x + −1/8x + −1/4 = 2

(1/16x + −1/8x)+(−1/4) = 2

Combine Like Terms

−1/16x + −1/4 = 2

Add 1/4 to both sides.

−1/16x + −1/4 + 1/4 = 2 + 1/4

−1/16x = 9/4

Multiply both sides by 16/(-1).

(16/−1)*(−1/16x)=(16/−1)*(9/4)

x=−36

3 0

3 years ago

A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of t

olasank [31]

Answer:

64x⁶ - 216y³

Step-by-step explanation:

The formula for the volume of a cube is

Vol. = l³

For the large cube,

V =(4x²)³

V = 64x⁶

For the small cube,

v =(6y)³

v = 216y³

The difference in volume is

Diff. = 64x⁶ - 216y³

5 0

3 years ago

Read 2 more answers

If a^2 + b^2=c^2 then the triangle is a right triangle.

NARA [144]

Answer:

False

Step-by-step explanation:

Measurements are too long on the A leg and B leg for it to be connected by a 12 in leg.

4 0

3 years ago

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

4 0

3 years ago