Question

What are the x and y intercepts of the equation y=log(3x+3)-2

Answer 1

$y \: = \: log(3x \: + \: 3) \: - \: 2$
For x-intercept,
y = 0,
log(3x+3) = 2
(3x + 3) = antilog(2)
x = (antilog(2) - 3)/3
x ≈ 32.3333
For y-intercept,
x = 0,
y = log(3) - 2
y ≈ -1.5228