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3 years ago

There are 5 times more boys than girls total number of students is 2814

Mathematics

1 answer:

DiKsa [7]3 years ago

8 0

What are u trying to ask the number of boys or girls or both?

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Based on given information for each of the following, which lines cannot be parallel? a m∠2=127°, m∠3=63°\ PLZZSZZZ help :>

tia_tia [17]

Answer:

Lines m and n cannot be parallel

Step-by-step explanation:

1. Because angles 2 and 3 are Same Side Interior Angles, they must be supplementary.

2. To check this you add the angles together (127 + 63) and it sums to 190 degrees, not 180

3. Since they don't agree with the laws of parallel lines, the lines that the angles are on can't be parallel

4. Angles 2 and 3 reside on lines m and n so lines m and n cannot be parallel

7 0

2 years ago

Three dump trucks are carrying topsoil to a construction site. Truck A carries 3,545 lb, Truck 8 carries 1,758 lb, and Truck C c

VikaD [51]

The total weight being carried is
3545 +1758 +3697 = 9000 . . . . . pounds

Each ton is 2000 pounds, so together the trucks are carrying
(9000 lb) × (1 t)/(2000 lb) = 4.5 t

Altogether, the 3 trucks are carrying 4.5 tons of topsoil.

8 0

3 years ago

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Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod

goblinko [34]

$(2+3)^{-1}\equiv5^{-1}\pmod7$ is the number L such that

$5L\equiv1\pmod7$

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so L = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

$2a\equiv1\pmod7\implies a\equiv4\pmod7$

since 2*4 = 8, whose residue is 1 mod 7;

$3b\equiv1\pmod7\implies b\equiv5\pmod7$

which we got for free by finding the inverse of 5 earlier. So

$2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7$

and so R = 2.

Then L - R = 1.

6 0

2 years ago

29.19 ÷ 0.3 Round your answer to the nearest hundredth.

Kobotan [32]

Answer: 97.0

Step-by-step explanation:

6 0

2 years ago

Write a quadratic equation that can be solved by factoring. Solve your equation and show and explain all your work.

miv72 [106K]

Answer:

An example of a quadratic equation is:

${x}^{2} + 5x + 6 = 0$

Step-by-step explanation:

This answer follows the standard form for a quadratic equation:

$a {x}^{2} + bx + c = 0$

To solve this equation you do the following:

x^2 + 5x + 6 =0

The factors that can be added to get *5* and multiplied to get *6* are 3 & 2.

Therefore the new equation would be:

x^2 +3x + 2x + 6 = 0

group the terms: (x^2 +3x) (+2x + 6) = 0

factorize: x (x + 3) 2 (x + 3) = 0

therefore: (x + 2) (x + 3) =0

x = -1 x =-3

4 0

1 year ago

Read 2 more answers