Answer:
So, the correct option is A. x = 9, y = 14 , Sides are 11 and 20
Step-by-step explanation:
P.S - the exact question is -
As given in the question ,
Side AB = Side AD
⇒y - 3 = x + 2
⇒y - x = 2 + 3 = 5
⇒y - x = 5 .........(1)
Also, given
Side BC = Side CD
⇒2x + 2 = x + 11
⇒2x - x = 11 - 2
⇒x = 9
∴ equation (1) becomes
y - 9 = 5
⇒y = 5 + 9 = 14
⇒y = 14
∴ we get
x = 9, y = 14
Now,
as given ,
Side AB = y - 3
⇒ AB = 14 - 3 = 11
Side BC = 2x + 2
⇒ BC = 2(9) + 2 = 18 + 2 = 20
Side CD = x + 11
⇒ CD = 9 + 11 = 20
Side DA = x + 2
⇒DA = 9 + 2 = 11
∴ we get
The sides are 11 and 20
So,
The correct option is A. x = 9, y = 14 , Sides are 11 and 20
Answer: I guess b I don’t really know hope you get better help
Step-by-step explanation:
Hello, I am papaguy Your answer is ready.
Answer: D. 225 words in 5 mins.
Answer:
![\displaystyle Range: \\ Set-Builder\:Notation → y|1 ≥ y ≥ -1 \\ Interval\:Notation → [-1, 1] \\ \\ Domain: \\ Set-Builder\:Notation → x|x ∈ R \\ Interval\:Notation → (-∞, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Range%3A%20%5C%5C%20Set-Builder%5C%3ANotation%20%E2%86%92%20y%7C1%20%E2%89%A5%20y%20%E2%89%A5%20-1%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-1%2C%201%5D%20%5C%5C%20%5C%5C%20Domain%3A%20%5C%5C%20Set-Builder%5C%3ANotation%20%E2%86%92%20x%7Cx%20%E2%88%88%20R%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%28-%E2%88%9E%2C%20%E2%88%9E%29)
Step-by-step explanation:
This is the graph of 
in which its AMPLITUDE [<em>A</em>] ALWAYS starts ONE BLOCK ABOVE the <em>midline</em><em>.</em><em> </em>In the trigonometric formula below, −C gives the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle y = Acos[Bx - C] + D](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%20Acos%5BBx%20-%20C%5D%20%2B%20D)
NOTE: Depending on how your trigonometric graphs are structured, your vertical shift [<em>D</em>] might tell you to space out the amplitude of the graphs alot more evenly on both ends.
<u>Extended</u><u> </u><u>Information on</u><u> </u><u>Trigonometric</u><u> </u><u>Graphs</u>
![\displaystyle Vertical\:Shift = D \\ Phase\:Shift\:[Horizontal\:Shift] = \frac{C}{B} \\ Period = \frac{2}{B}π \\ Amplitude = |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%3D%20D%20%5C%5C%20Phase%5C%3AShift%5C%3A%5BHorizontal%5C%3AShift%5D%20%3D%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%3D%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%3D%20%7CA%7C)
I am joyous to assist you anytime.
For this case, the first thing to do is find the equation of the line in order to model the problem mathematically.
Using Excel (see attached image) we find that the equation of the line is:
y = 0.0035x - 3 We evaluate for:
For x = 7000: y = 0.0035 * (7000) - 3
y = 21.5 $
For x = 10000 y = 0.0035 * (10000) - 3
y = 32 $
For x = 13000 y = 0.0035 * (13000) - 3
y = 42.5 $
Answer: The total water cost when the barber shop uses 7,000 gallons, 10,000 gallons, and 13,000 gallons is: 21.5 $, 32 $, 42.5 $, respectively.
