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3 years ago

Using multiplication property of equality solve x/2=6

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

Answer:

x=12

Step-by-step explanation:

↓↓↓↓↓↓↓↓↓↓↓↓

Multiplication property of equality is multiply both sides of an equation by the same number does not change the equation.

$\frac{x}{2}=6$

multiply two both sides

$\frac{2x}{2}=6*2$

simplify

$6*2=12$

$12/2=6$

$12/6=2$

$2*6=12$

$x=12$

Hope this helps!

weeeeeb [17]3 years ago

5 0

$\frac{x}{2}$ = 6
$\frac{x}{2}$ (2) = 6(2)
x=12

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nignag [31]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

Which two values of x are roots of the polynomial below? x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

Solution:

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$