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2 years ago

3 and 1/13 in simplest form.

Mathematics

2 answers:

defon2 years ago

8 0

Answer:

3 1/3 is already in the simplest form. It can be written as 0.230769 in decimal form (rounded to 6 decimal places).

Have an awesome day! :D

irina1246 [14]2 years ago

3 0

Answer: it's already in simplest form

Step-by-step explanation:

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X^2/9+2y/7 help me solve

vfiekz [6]

So firstly, we have to find the LCD, or lowest common denominator, of 9 and 7. To do this, list the multiples of 9 and 7 and the lowest multiple they share is going to be your LCD. In this case, the LCD of 9 and 7 is 63. Multiply x^2/9 by 7/7 and 2y/7 by 9/9:

$\frac{x^2}{9}\times \frac{7}{7}=\frac{7x^2}{63}\\\\\frac{2y}{7}\times \frac{9}{9}=\frac{18y}{63}\\\\\frac{7x^2}{63}+\frac{18y}{63}$

Next, add the numerators together, and your answer will be: $\frac{7x^2}{63}+\frac{18y}{63}=\frac{7x^2+18y}{63}$

4 0

3 years ago

HELP PLS QUICK MIGHT GIVE BRAINLIST ONLY IF 2 PEOPLE ANSWER!

Afina-wow [57]

Answer:

area = 10 squares units

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5 0

3 years ago

Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ

gulaghasi [49]

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf = {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf = 30184 / 1241

Δf = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

6 0

3 years ago

I need help on. this question. (3x^6)^3 the answer must have one exponent

kotykmax [81]

Answer:

$27x^{18}$

Step-by-step explanation:

$\left(3x^6\right)^3$

Separate $3x^6$ :

$3^3\times\left(x^6\right)^3$

$27\times\left(x^6\right)^3$

$27x^{6\times3}$

$27x^{18}$

5 0

3 years ago

Question 7: 10 pts

levacccp [35]

The teacher ordered the students in 24 ways.

We have given that the total number of students is 4.

4 students are assigned to give presentations.

We have to find the arrangement of the 4 students.

<h3>What is the arrangement?</h3>

An arrangement (or ordering) of a set of objects is called a permutation. (We can also arrange just part of the set of objects.)

In a permutation, the order that we arrange the objects n is important.

4 students can be arranged by 4! ways.

$4!=4*3*2*1\\ =12*2\\=24$

Therefore option 3 is correct.

The teacher ordered the students in 24 ways.

To learn more about the permutation visit:

brainly.com/question/12468032

#SPJ1

3 0

2 years ago