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2 years ago

3 and 1/13 in simplest form.

Mathematics

2 answers:

defon2 years ago

8 0

Answer:

3 1/3 is already in the simplest form. It can be written as 0.230769 in decimal form (rounded to 6 decimal places).

Have an awesome day! :D

irina1246 [14]2 years ago

3 0

Answer: it's already in simplest form

Step-by-step explanation:

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If both slopes are undefined are they parallel?

SCORPION-xisa [38]

Answer:

If the slopes of the lines are both zero, the lines are horizontal and are parallel by definition. Since the slopes of vertical lines are undefined and not considered equal, vertical lines will not be considered.

I hope this helps you :)

8 0

2 years ago

Just need the answer. it was "Check all that apply." at the end.

lianna [129]

Billy, let's recall what a linear pair of angles is:

• They are formed when two lines intersect.

• Two angles are said to be linear if they are adjacent angles formed by two intersecting lines.

• The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Upon saying that we have that:

• CAD and DAE are linear pairs

• CAD and CAB are linear pairs

• DAE and BAE are linear pairs

• DAE and DAC are linear pairs

Now, you are ready to select all the options that actually apply.

3 0

1 year ago

Evaluate the variable expression when a = 5, b = 5, and c = -4. Bc divided by (2a)

zlopas [31]

Answer:

-2

Step-by-step explanation:

Bc÷2a

5×-4÷2×5

-20÷10

-2

6 0

3 years ago

Read 2 more answers

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

5 0

3 years ago

Read 2 more answers

Simplify the following: 0.9√86 2√131

dimulka [17.4K]

OK
The first one would be
8.34625

The second one would be
22.89104

H0P3 It H3LPS :)

6 0

2 years ago