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LekaFEV [45]
3 years ago
10

Which of the following expressions does not mean the same as the other three?

Mathematics
1 answer:
White raven [17]3 years ago
3 0
What are the expressions 
marty
2 years ago
x - 17 x - (-17) x + (-17) - 17 + x
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(1 point) A student was asked to find the equation of the tangent plane to the surface z=x2−y3 at the point (x,y)=(5,1). The stu
Nonamiya [84]

Answer:

Options a and d are the correct ones.

Step-by-step explanation:

The complete question is as follows

A student was asked to find the equation of the tangent plane to the surface z = x^2-y^3 at the point (x,y)=(5,1). The student's answer was  z = 24+2x(x-5)-3y^2(y-1). (a) At a glance, how do you know this is wrong. What mistakes did the student make? Select all that apply.

a) The answer is not a linear function

b) The (x-5) and (y-1) should be x and y

c) the 24 should not be in the answer

d) the partial derivatives were not evaluated at the point

e) all of the above.

Recall that, given a surface of the form z=f(x,y) where f is differentiable, then at a given point (x_0,y_0) we can find the equation of the tangent plane by

z=f(x_0,y_0)+\frac{df}{dx}(x_0,y_0) (x-x_0)+\frac{df}{dy}(x_0,y_0) (y-y_0)

We are given that (x_0,y_0) = (5,1) Note that f(5,1) = 24. Then, c is not true. Also, the formula says that we must have the factors (x-5) and (y-1), since we are evaluating the tangent plane in a neighborhood of that point, hence option b is not true. Since B and C are not true, then E is not true. Note that the given function by the student has a mutiplication of 2x and (x-5) which will give us the function 2x^2-10 which is of degree two. Then, the function given by the student is not a linear function, since linear functions have a degree at most 1. Finally, we must check that d is also true.

REcall that

\frac{df}{dx} = 2x, \frac{df}{dy} = -3y^2

so we see that this coincide with the the terms that multiply the factors (x-5) and (y-1) respectively, which tell us that even though the student was trying to follow the formula, he/she forgot to evaluate the partial derivatives at the given point, hence the option D is also true.

Recall that if we want the tangent plane at the point given, we must evaluate the partial derivatives at x=5 and y=1. Hence, the formula of the tangent plane is

z = 24+10(x-5)-3(y-1)

5 0
2 years ago
I really need help, please and thank you
Citrus2011 [14]
I think it’s (A) I’m not sure...sorry if it’s wrong
7 0
3 years ago
In the diagram below, AC is perpendicular to BD. Find the value of N.
timurjin [86]
Hi there!

In order to find the value of N, we'll need to set the value of the angle containing the variable n equal to 90. This is because in perpendicular lines, all angles are equal to 90.

WORK:
5n - 25 = 90
5n = 115
n = 23
8 0
2 years ago
The isosceles trapezoid is part of an isosceles triangle with a 32° vertex angle. What is the measure of an acute base angle of
nevsk [136]

Answer:

acute base angle = 74° , obtuse base angle = 106°

Step-by-step explanation:

Since the large triangle is isosceles with vertex angle (top angle) is 32, then the bottom 2 angles would be same (let it be x):

We know angles of triangle add up to 180, so we have:

x + x + 32 = 180

2x = 180 - 32

2x = 148

x = 148/2

x = 74

This 74 degree angle is the base acute angle of the isosceles trapezoid (lower portion). We also know opposite angles of isosceles trapezoid are supplementary (add up to 180), thus

obtuse angle + 74 = 180

obtuse angle (base) = 180 - 74 = 106

Thus, acute base angle = 74° , obtuse base angle = 106°

6 0
3 years ago
PLEASE HELP ASAP!!
Art [367]

Answer:

See explanation

Step-by-step explanation:

A.  P(top)=top outcomes/all kinds of outcomes=4/30=2/15=13.33333333333...%

P(bottom)=bottom outcomes/ all kinds of outcomes=1/30=3.33333333....%

P(side)=25/30=5/6=83.33333333333...%

B. No. If were equally likely, the probabilities for A would have been roughly the same. It seems like the side event is more probable.

7 0
3 years ago
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