Owen measured a line to be 17.9 inches long. If the actual length of the line is 17.8 inches, then what was the percent error of
the measurement, to the nearest tenth of a percent?
2 answers:
Answer:
0.6%
Step-by-step explanation:
Percent Error = the absolute value of (actual value observed-expected value)/(expected value) x100%
(17.8-17.9)/(17.9) = -0.006
Absolute value is 0.006
0.006 times 100% equals 0.6%
Answer:
0.6 %
Step-by-step explanation:
percentage error=(17.9-17.8)/17.8 ×100=1/178×100=100/178=50/89≈0.56≈0.6
You might be interested in
Answer:
$137.50
Step-by-step explanation:
11,000 x .15 (100-.85)=$1.650 amount she will have to pay annually.
$1,650/12months = $137.50 is minimum to save monthly.
Answer:
129°
Step-by-step explanation:
51+51 =102
360-102=258
258÷2=129
:)
Answer:
7b-c²
Step-by-step explanation:
7times b is 7b reduced by the square of c means minus c²
The product is -10y² -19y +15.
I believe the answer is 17