Rounded to the thousands would be 307,000 and thousandths is 307.407
Let X be the weekly incomes of a large group of executives. The weekly incomes of a large group of executives follows Normal distribution with mean $2000 and standard deviation $100.
μ =2000, σ =100
We have to find z score for income $2100 i.e x=2100
Z = 
= 
Z = 100/100
Z = 1
The z score for income $2100 is 1
When x= -5, y= 34; when y= 64, x = -10