N is an odd integer
The Next Larger is N+2
N+2 + 2N = -27 + 4N
3N + 2 = 4N - 27
0 = 4N - 27 - 3N - 2
0 = N - 29
N = 29
They are 29 and 31.
31 + 2(29) = 4(29) - 27
31 + 58 = 89 = 116 - 27 yes it works
Answer:
Step-by-step explanation: ok
<h3>3
Answers:</h3>
- B) Mean
- C) Mean absolute deviation
- E) Mode
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Explanation:
The box plot, aka "box-and-whisker plot", visually represents five things. These things are:
- Minimum
- Q1 = first quartile
- Median (sometimes referred to as Q2 or second quartile)
- Q3 = third quartile
- Maximum
This list of five items is known as the five number summary.
The min is the tip of the left most whisker, assuming there aren't any small outliers. The max is the opposite side, being the tip of the right most whisker (assuming no large outliers). If there are any outliers, then they'll be shown as "island" dots on their own separated from the main box plot. The left and right edges of the box are Q1 and Q3 respectively. The median is the vertical line inside the box. The vertical line does not have to be at the midpoint of the left and right edges of the box. It simply needs to be somewhere in the box.
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Since the box plot lets us know the min and max, we can compute the range because
range = max - min
and we can also calculate the interquartile range (IQR) because
IQR = Q3 - Q1
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So to summarize so far, the five number summary is visually represented as the box plot. The range and IQR can be computed using items from the five number summary.
We cannot compute the mean because we would need the actual data set of values, rather than the summary data. The same goes for the mean absolute deviation (MAD) and the mode. Since your teacher is looking for things that cannot be determined from a box plot, we'll go for answers B, C and E.
In other words, we rule out choices A, D, and F because we can compute or determine those values from a box plot.
if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.
so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.
so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.
or using a unit vector for those above, then
