Answer:
![\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%3D%28a%5E%7B2%7D%2Bb%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
Step-by-step explanation:
∵∛x = (x)^1/3
∴ ![\sqrt[3]{a^{2}+b^{2}}=(a^{2}+b^{2})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%3D%28a%5E%7B2%7D%2Bb%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
So you can replace the radicals by fractional exponents
one and twelve thirty fifths Step-by-step explanation:
Well 100 ÷ 4 = 24 so 3/4 =75/100 and three hours before ten would be 7:00 then you take fourth minutes from the remainder ( 30 mins) and it had to go back an hour because you can't do 30-40 (don't stubtract in time but for this you can you just have to know that 60 mins= 1hr and don't EVER do this: 5:75 <- this is incorrect time.)
umm... 6:50?
I would solve for y on the top one and sub it into the bottom one.
y=-2x+8
(12/5, 16/5)